A naval station sees waves with 5.6 meters between crests, and these waves hit the station every 4.25 seconds.
1 answer:
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Answer:
The final velocity of the runner at the end of the given time is 2.7 m/s.
Explanation:
Given;
initial velocity of the runner, u = 1.1 m/s
constant acceleration, a = 0.8 m/s²
time of motion, t = 2.0 s
The velocity of the runner at the end of the given time is calculate as;
where;
v is the final velocity of the runner at the end of the given time;
v = 1.1 + (0.8)(2)
v = 2.7 m/s
Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
- Total time = 2.340 – 0 = 2.340 h
- Total distance = 16.3 – 0 = 16.3 Km
- Average speed =?
Learn more about average speed: brainly.com/question/24884027
The image position is 13.9 cm from the mirror
Explanation:
To solve this problem, we can use the mirror equation:
where
f is the focal length
p is the distance of the object from the mirror
q is the distance of the image from the mirror
In this problem, we have:
f = 3.4 cm is the focal length of the mirror (positive for a concave mirror)
p = 4.5 cm is the position of the object (the tree)
Solving the equation for q, we find the position of the image:
Learn more about mirrors:
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