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Juliette [100K]
3 years ago
13

If 1.3 grams of air has a volume of 1000cm ^3, what is the density of air?

Physics
2 answers:
sleet_krkn [62]3 years ago
5 0
D)
Density is equal to mass/volume, so in your case:
density=1.3/1000=0.0013 g/cm^3
Daniel [21]3 years ago
5 0

Answer:

Density, d=0.0013\ g/cm^3

Explanation:

Given that,

Mass of the air, m = 1.3 grams

Volume of the air, V=1000\ cm^3

The density of the air is given by total mass divided by total volume. Mathematically, it is given by :

d=\dfrac{m}{V}

d=\dfrac{1.3\ g}{1000\ cm^3}

d=0.0013\ g/cm^3

Hence, this is the required solution.

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In 3 meters a person running 0.5 m/s accelerates 1.2 m/s 2. How fast were they going afterward? Choose the right equation for th
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Answer:

2.72 m/s

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In 3 meters a person running 0.5 m/s accelerates 1.2 m/s².

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Acceleration, a = 1.2 m/s²

We need to find the final velocity of the person. Using equation of motion to find it as follows :

v^2-u^2=2as\\\\v^2=2as+u^2\\\\v^2=2\times 1.2\times 3+(0.5)^2\\\\v=2.72\ m/s

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. Consider a fully extended arm that is rotating about the shoulder such that with a shoulder-to-hand length of 30 cm. If the ar
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Answer:

13.309 m/s²

Explanation:

Length from shoulder to hand, l = 30 cm = 0.3 m

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Let the tangential acceleration is a.

by using first equation of motion

v = u + at

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a = 0.5 m/s²

Let the centripetal acceleration is a'.

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