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Juliette [100K]
3 years ago
13

If 1.3 grams of air has a volume of 1000cm ^3, what is the density of air?

Physics
2 answers:
sleet_krkn [62]3 years ago
5 0
D)
Density is equal to mass/volume, so in your case:
density=1.3/1000=0.0013 g/cm^3
Daniel [21]3 years ago
5 0

Answer:

Density, d=0.0013\ g/cm^3

Explanation:

Given that,

Mass of the air, m = 1.3 grams

Volume of the air, V=1000\ cm^3

The density of the air is given by total mass divided by total volume. Mathematically, it is given by :

d=\dfrac{m}{V}

d=\dfrac{1.3\ g}{1000\ cm^3}

d=0.0013\ g/cm^3

Hence, this is the required solution.

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A sled slides down a hill with friction between the sled and hill but negligible alr resistance. Which of the following must be
Andreyy89

Answer:

A) The sum of the kinetic energy and the gravitational potential energy changes by an amount equal to the energy dissipated by friction,

Explanation:

  • The kinetic energy is the energy that the object has and is defied by the work that is needed to accelerate the body.
  • The gravitational potential is a mechanism by which an equal amount of energy is being transferred per unit mass that is needed for the object to move from the specific location.
  • Hence when the sled moves down the hill with the force of gravity it has negligible resistance as an equal amount of energy is dissipated.
8 0
3 years ago
A pilot in a small plane encounters shifting winds. He flies 26.0 km northeast, then 45.0 km due north. From this point, he flie
cluponka [151]

Answer:

a) v₃ = 19.54 km, b)  70.2º north-west

Explanation:

This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition

vector 1 moves 26 km northeast

let's use trigonometry to find its components

         cos 45 = x₁ / V₁

         sin 45 = y₁ / V₁

         x₁ = v₁ cos 45

         y₁ = v₁ sin 45

         x₁ = 26 cos 45

         y₁ = 26 sin 45

         x₁ = 18.38 km

         y₁ = 18.38 km

Vector 2 moves 45 km north

        y₂ = 45 km

Unknown 3 vector

          x3 =?

          y3 =?

Vector Resulting 70 km north of the starting point

           R_y = 70 km

we make the sum on each axis

X axis

      Rₓ = x₁ + x₃

       x₃ = Rₓ -x₁

       x₃ = 0 - 18.38

       x₃ = -18.38 km

Y Axis

      R_y = y₁ + y₂ + y₃

       y₃ = R_y - y₁ -y₂

       y₃ = 70 -18.38 - 45

       y₃ = 6.62 km

the vector of the third leg of the journey is

         v₃ = (-18.38 i ^ +6.62 j^ ) km

let's use the Pythagorean theorem to find the length

         v₃ = √ (18.38² + 6.62²)

         v₃ = 19.54 km

to find the angle let's use trigonometry

           tan θ = y₃ / x₃

           θ = tan⁻¹ (y₃ / x₃)

           θ = tan⁻¹ (6.62 / (- 18.38))

           θ = -19.8º

with respect to the x axis, if we measure this angle from the positive side of the x axis it is

          θ’= 180 -19.8

          θ’= 160.19º

I mean the address is

          θ’’ = 90-19.8

          θ = 70.2º

70.2º north-west

3 0
3 years ago
If two balls have the same volume,
Lena [83]

Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

  • 1. Ball A will have the greater density
  • 2. Ball C and Ball D have the same density.
  • 3. Ball Q will have the greater density.
  • 4. Ball X and Y will have the same density

The density of an object is given as its mass per unit volume of the object.

Mathematically;.

  • Density = Mass/Volume.

For Case 1:

  • Va = Vb and Ma = 2Mb
  • D(b) = (Mb)/(Vb) and D(a) = 2(Mb)/Vb
  • Therefore, the density of ball A,
  • D(a) = 2D(b).
  • Therefore, ball A has the greater density.

For Case 2:

  • Vc = 3Vd,

  • Vd = (1/3)Vc

  • Md = (1/3)Mc

  • D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd

  • D(c) = D(d).

  • Therefore, ball C and D have the same density

For Case 3:

  • Vp = 2Vq and Mp = Mq
  • D(p) = (Mq)/2(Vq) and D(q) = (Mq)/Vq
  • Therefore, the density of ball P is half the density of ball Q
  • Therefore, ball Q has the greater density.

For case 4:

  • Mx = (1/2)My
  • Vx = Vy

Therefore, Ball X and Ball Y have the same density.

Read more:

brainly.com/question/18110802

8 0
2 years ago
Which use of iron is due to its chemical properties?
AfilCa [17]
Colored sparks and rusting.
3 0
2 years ago
What provides the force on the person in the passenger seat?
podryga [215]

The forces that make a passenger speed up, slow down, or
turn a curve are the same forces that have the same effect
on the driver and anybody else in the car.

-- Speeding up . . .

              the back of the seat
              friction between the car seat and the seat of your pants

-- Slowing down . . .

              the seat belt
              friction between the car seat and the seat of your pants

-- Turning away from a straight line . . .
   
              the seat belt
              friction between the car seat and the seat of your pants
              the door, or whatever or whomever you're leaning against

6 0
3 years ago
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