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Leto [7]
3 years ago
9

Two blocks have mass m and M=2.77 m, respectively. A light spring is attached to one of them, and the blocksare pushed together,

compressing the spring between them. They are secured, in this compressed state, by a cord. They are then placed, at rest, on a horizontal frictionless surface. The cord holding them together is burned, after which the block of mass M moves to the right with a speed of 1.38 m/s. What is the speed of the block of mass m? Answer in units of m/s
Physics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

3.8226 m/s

Explanation:

Momentum is conserved hence

equating momentum, p

p (before) = p (after)

0 = (m1v1)+(M2v2)  but m2=2.77m where m and v are the masses and velocity respectively

0 = (mv1) +(2.77m)(1.38)

(mv1)=-(2.77m)(1.38)

(v1)=-(2.77)(1.38)

Solving v1

v1 = - 3.8226 m/s

= 3.8226 m/s, to the left

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3 years ago
If the magnitude of the magnetic field is 6.50 mT at a distance of 12.8 cm from a long straight current carrying wire, what is t
Lunna [17]

Answer: magnitude of the magnetic field at a distance of 19.4 cm from the wire=4.29mT

Explanation:

According to  Biot-Savart law, A magnetic field generated by a current  carrying wire at a distance is represented as

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B = magnetic field intensity 1000 mT =1T, 6.50mT = 6.50 X 10^-3T

 μ₀ =permeability of free space  4π × 10−7 H/m

I = current intensity

r = radius, 100cm = 1m, 12.8 cm= 12.8 x 10^-2m

6.50 X 10^-3 =  μ₀ x I/ 2 π X 12.8 X 10^-2

I =6.50  X 10 ^-3 X 2π  X  X 12.8 X 10^-2/  4π × 10−7 H/m

I= 4160 A

when the magnetic field is at 19.4 cm from the wire

B=μ₀I/ 2πr

= 4π × 10−7 H/m x4160/ 2π x 19.4 x 10^-2

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7 0
3 years ago
The radius of curvature of both sides of a converging lens is 18 cm. One side of the lens is coated withsilver so that the inner
Dahasolnce [82]

Answer:

n = 1.4

Explanation:

Given,

R1 = 18 cm, R2 = -18 cm

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f = 9/(n-1)

Power, P = 1/f ( in m) = (n-1)/0.09

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Net power of the combination = 2P + P' = 2(n-1)/0.09 + 1/0.09 = 1/0.05

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Hope I helped you :)
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