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alex41 [277]
4 years ago
5

The ratio of 1kWh to 1MeV

Physics
1 answer:
Wittaler [7]4 years ago
8 0

Answer:

You can use a calculator on Google or search an app

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A car traveling 25 m/s to the north collides with a car traveling 15 m/s to the south. Each car has a mass of 1100 kg. If the sy
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A 5000kg car traveling at 40m/s crashes into a wall and comes to a complete stop in 10s. What was the force on the wall? solve s
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Answer:

20,000 N

Explanation:

First find the acceleration:

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a = (0 − 40 m/s) / 10 s

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Next use Newton's second law to find the force on the car:

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I shared a picture of the problem. It’s a basic Physics question and an Algebra question.
julia-pushkina [17]

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

Given the expressions;

T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}

Equating both expressions we will have;

2 \pi \sqrt{\frac{m}{k} }  = \frac{2 \pi}{\omega}

Divide both equations by 2π

\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\

Square both sides

(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}

Take the square root of both sides

\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}

Hence the expression of ω in terms of m and k is

\omega = \sqrt{\frac{k}{m}

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Boiling point of water is 100 deg C. It takes about 540 cal to change 1 g of water at the boiling point to 1 g of steam at 100 deg C.

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