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asambeis [7]
3 years ago
5

Between any two points (x1, f(x1)) and (x2, f(x2)) is the slope of the line through the two points, and this line is called the

Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

secant hopefully that'll help :)

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F(t) = 2t - 3 evaluate the function
Olenka [21]

Answer:

t ∈   ℝ

Step-by-step explanation:

6 0
3 years ago
What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9
Bas_tet [7]

Answer:

  no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

  \dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0
3 years ago
Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2
Gemiola [76]
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
a = b = c \div  \sqrt{2} \\ c  = a\sqrt{2}  \\ c = 6 \sqrt{2} \times \sqrt{2}  = 6 \times 2 = 12
Another way to do it is the longer proof of Pythagorean Theorem:
{c}^{2}  =  {a}^{2}  +  {b}^{2}... \:  \:  c =   \sqrt{({a}^{2}  +  {b}^{2})}  \\
c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}}  \\ =  \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )}  =  \sqrt{2(36 \times 2)}  \\ c =  \sqrt{144}  = 12

7 0
3 years ago
Which of the following transformations are used when transforming the graph of the parent function...
hram777 [196]

1. 1st transformation is translation the parent function y=\log_5x 6 units to the right to get the function y=\log_5(x-6).

2. 2nd transformation is reflection the function y=\log_5(x-6) over the x-axis. This transformation gives you the function y=-\log_5(x-6).

3. 3rd transformation is vertical stretch of the function y=-\log_5(x-6) by a factor of 2 to get the function y=-2\log_5(x-6).

Only last two are present in options, then

answer: C and D.

5 0
3 years ago
A college student has 700$ in their account she spends $165 from the account on books and then deposits $190 in the account how
adell [148]

Hello,

I hope so far you and your family are staying safe and healthy!

We need to solve this step by step.

The college student has $700 in their account.  But then she spends $165 on books from that money. So we need to Subtract that.

700 - 165 =535

However, later on, she deposits $190 to the same account. So we need to take the remain we had and add it to the new amount.

535 + 190 = 725

Thus,

There are $725 in the account.

I wish you all the best!

~Gary

4 0
3 years ago
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