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Murrr4er [49]
3 years ago
11

An aqueous solution of ____ will produce a basic solution.

Chemistry
2 answers:
lyudmila [28]3 years ago
8 0

Hydrolysis of NH_{4}ClO_{4} is given as:

NH_{4}ClO_{4}+H_{2}O\rightleftharpoons NH_{4}OH + HClO_{4}

Here, NH_{4}OH is a   weak base and HClO_{4} is a strong acid. Thus, solution is more acidic

Hydrolysis of KBr is given as:

KBr+H_{2}O\rightleftharpoons KOH  +   HBr

Here, KOH is a strong base and HBr is a strong acid.Thus, solution is neutral.

Hydrolysis of NaCl is given as:

NaCl+H_{2}O\rightleftharpoons NaOH  + HCl

Here, NaOH is a strong base and HCl is a strong acid.Thus, solution is neutral.

Na_{2}CO_{3}+2H_{2}O\rightleftharpoons  2NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.      

NaHCO_{3}+H_{2}O\rightleftharpoons  NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.        

Hence, an aqueous solution of  NaHCO_{3} and Na_{2}CO_{3} will produce a basic solution.





Anastasy [175]3 years ago
6 0
NaClO, K2CO3, and NaF will form basic soltions.

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he thermite reaction, in which powdered aluminum reacts with iron(III) oxide, is highly exothermic. 2 Al(s) + Fe2O3(s) Al2O3(s)
Afina-wow [57]

The given question is incomplete. The complete question is

The thermite reaction, in which powdered aluminum reacts with iron oxide, is highly exothermic: 2Al(s)+Fe_2O_3(s)\rightarrow Al_2O_3(s)+2Fe(s). Use standard enthalpies of formation to find ΔH∘rxn for the thermite reaction. Express the heat of the reaction in kilojoules to four significant figures.

Answer: ΔH∘rxn for the thermite reaction is -851.5 kJ

Explanation:

The balanced chemical reaction is :

2Al(s)+Fe_2O_3(s)\rightarrow Al_2O_3(s)+2Fe(s)

We have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{Fe}\times \Delta H_f^0_{(Fe)}+n_{Al_2O_3}\times \Delta H_f^0_{(Al_2O_3)}]-[n_{Al}\times \Delta H_f^0_(Al)+n_{Fe_2O_3}\times \Delta H_f^0_{(Fe_2O_3)}]

where,

We are given:

\Delta H^o_f_{(Fe_2O_3(s))}=-824.2kJ/mol\\\Delta H^o_f_{(Al_2O_3(s))}=-1675.7kJ/mol\\\Delta H^o_f_{(Fe(s))}=0kJ/mol\\\Delta H^o_f_{(Al(s)}=0kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times 0)+(1\times -1675.5)]-[(2\times 0)+(1\times -824.2)]=-851.5kJ

ΔH∘rxn for the thermite reaction is -851.5 kJ

4 0
3 years ago
What will be the substitution product of (S)-2-chloro-3-methylbutane in polar aprotic conditions favoring SN2?
Deffense [45]
Almost there use socratic app



it will help


3 0
3 years ago
I need help plz with the first question plz
Cloud [144]
Ok so put it in order
7 0
3 years ago
Question 1 (1 point)
stealth61 [152]

Answer:

Q1: 9

Q2:10

Q3: 50

Q4:True

Q5: False

Q6:False

Q7:True

Explanation: Just took the quiz

6 0
3 years ago
Two tons of water is pumped into a tank 15 ft. High in 5 minutes. Determine the power output of the pump. (Note: One ton is equa
Semmy [17]

Answer:

200 lb•ft/s

Explanation:

From the question given above, the following data were obtained:

Force (F) = 2 tons

Time (t) = 5 mins

Height (h) = 15 ft

Power (P) =?

Next, we shall convert 2 tons to pound. This can be obtained as follow:

1 ton = 2000 lb

Therefore,

2 tons = 2 × 2000

2 tons = 4000 lb

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

5 mins = 5 × 60

5 mins = 300 s

Finally, we shall determine the power of the pump. This can be obtained as follow:

Force (F) = 4000 lb

Time (t) = 300 s

Height (h) = 15 ft

Power (P) =?

P = F × h / t

P = 4000 × 15 / 300

P = 60000 / 300

P = 200 lb•ft/s

Thus, the power of the pump is 200 lb•ft/s

5 0
2 years ago
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