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Murrr4er [49]
3 years ago
11

An aqueous solution of ____ will produce a basic solution.

Chemistry
2 answers:
lyudmila [28]3 years ago
8 0

Hydrolysis of NH_{4}ClO_{4} is given as:

NH_{4}ClO_{4}+H_{2}O\rightleftharpoons NH_{4}OH + HClO_{4}

Here, NH_{4}OH is a   weak base and HClO_{4} is a strong acid. Thus, solution is more acidic

Hydrolysis of KBr is given as:

KBr+H_{2}O\rightleftharpoons KOH  +   HBr

Here, KOH is a strong base and HBr is a strong acid.Thus, solution is neutral.

Hydrolysis of NaCl is given as:

NaCl+H_{2}O\rightleftharpoons NaOH  + HCl

Here, NaOH is a strong base and HCl is a strong acid.Thus, solution is neutral.

Na_{2}CO_{3}+2H_{2}O\rightleftharpoons  2NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.      

NaHCO_{3}+H_{2}O\rightleftharpoons  NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.        

Hence, an aqueous solution of  NaHCO_{3} and Na_{2}CO_{3} will produce a basic solution.





Anastasy [175]3 years ago
6 0
NaClO, K2CO3, and NaF will form basic soltions.

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A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
sertanlavr [38]

Answer: The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.947 atm

P_2 = final pressure of gas = 0.987 atm

V_1 = initial volume of gas = 150 ml

V_2 = final volume of gas = 144 ml    

T_1 = initial temperature of gas = 25^0C=(25+273.15)K=298.15K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.947\times 150}{298.15}=\frac{0.987\times 144}{T_2}

T_2=298.31K=(298.31-273.15)^0C=25.16^0C

The temperature of the gas at a pressure of  0.987 atm and volume of 144mL is 25.16^0C

4 0
2 years ago
Choose two of the following scientists: Anton Lavoisier, John Dalton, JJ Thomson, Robert Millikan, Ernest Rutherford, James Chad
OverLord2011 [107]

Ernest Rutherford

J. J Thomson

Explanation:

<u>Ernest Rutherford</u>

In 1911, Ernest Rutherford, a New Zealand chemist performed the gold foil experiment where he gave the modelling of the atom a boost.

 Experiment

 In his experiment, he bombarded a thin gold foil with alpha particles generated from a radioactive source. He found that most of the alpha particles passed through the gold foil while a few of them were deflected back.

 Discovery and reflection on the atomic theory

To account for his observation, Rutherford suggested an atomic model in which an atom has small positively charged center where nearly all the mass is concentrated.

<u>J. J Thomson</u>

Experiment

In 1897 J.J Thomson performed experiments using the gas discharge tube that led to the discovery of the electrons. He called them cathode rays because they originate from the cathode and exits at the anode.

Discovery and reflection on the atomic theory

From his experiment on the gas discharge tube, Thomson was able determine the properties of cathode rays some of which are:

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Using his observation, he proposed the plum pudding model of the atom where it is made up of entirely electrons.

learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

6 0
3 years ago
Consider an electron with charge −e−e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with cha
PtichkaEL [24]

Answer:

Explanation:

The net force on electron is electrostatic force between electron and proton in the nucleus .

Fc = \frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}

This provides the centripetal force for the circular path of electron around the nucleus .

Centripetal force required = \frac{m\times v^2}{r}

So

\frac{m\times v^2}{r}=\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}

v^2=\frac{e^2}{4\pi \epsilon m r}

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3 years ago
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podryga [215]

Answer:

2H3PO4=H4P2O7+H2O

Explanation:

2H3PO4=H4P2O7+H2O

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suter [353]
The rate of reaction would increase because as pressure increases the molecules are more likely to bump into each other leading to a more likely hood of the molecules colliding properly to react leading to an increase in the reaction rate of the substance.
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3 years ago
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