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Murrr4er [49]
4 years ago
11

An aqueous solution of ____ will produce a basic solution.

Chemistry
2 answers:
lyudmila [28]4 years ago
8 0

Hydrolysis of NH_{4}ClO_{4} is given as:

NH_{4}ClO_{4}+H_{2}O\rightleftharpoons NH_{4}OH + HClO_{4}

Here, NH_{4}OH is a   weak base and HClO_{4} is a strong acid. Thus, solution is more acidic

Hydrolysis of KBr is given as:

KBr+H_{2}O\rightleftharpoons KOH  +   HBr

Here, KOH is a strong base and HBr is a strong acid.Thus, solution is neutral.

Hydrolysis of NaCl is given as:

NaCl+H_{2}O\rightleftharpoons NaOH  + HCl

Here, NaOH is a strong base and HCl is a strong acid.Thus, solution is neutral.

Na_{2}CO_{3}+2H_{2}O\rightleftharpoons  2NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.      

NaHCO_{3}+H_{2}O\rightleftharpoons  NaOH + H_{2}CO_{3}

Here, NaOH is a strong base and H_{2}CO_{3} is a weak acid.Thus, solution is basic.        

Hence, an aqueous solution of  NaHCO_{3} and Na_{2}CO_{3} will produce a basic solution.





Anastasy [175]4 years ago
6 0
NaClO, K2CO3, and NaF will form basic soltions.

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You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution
vfiekz [6]

Answer:

450. g of 0.173 % KCN solution contains 779 mg of KCN.

Explanation:

Mass of the solution = m

Mass of the KCN in solution = 779 mg

Mass by mass percentage of KCN solution = 0.173%

(m/m)\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

0.173\%=\frac{779 mg}{m}\times 100

m=\frac{779 mg}{0.173}\times 100= 450,289 mg

1 mg = 0.001 g

m = 450,289 mg × 0.001 g = 450.289 mg ≈ 450. g

450. g of 0.173 % KCN solution contains 779 mg of KCN.

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Hi there!

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