The product would be negative. Since there are three negative integers, the product would be negative. Two negatives make a positive, but another negative makes the end result negative.
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
Answer: X = 10.20240940...
Step-by-step explanation:
x(2x + 9) = 2x^2 + 9x
2x^2 + 9x = 300
- 300 ON BOTH SIDES
2x^2 + 9x - 300 = 0
SOLVE USING THE QUADRATIC FORMULA
x = -b +/- all root (b)^2 - 4(a)(c) All over 2(a)
When all the values are plugged in:
When using "+" in the equation you should get:
x = 10.20240940…
When using "-" in the equation you should get:
x = −14.70240940…
Now.. you CANNOT have a negative length, so you cross of the negative value leaving you one value for x which is 10.20240940...
YOUR ANSWER IS: x = 10.20240940...
The answer is A.
The 0's of the function are -2, 2, and 3.
The graph starts from the bottom left and it keeps going to the top right.
