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makkiz [27]
3 years ago
6

(25 points)

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0
X³ - 3x² - 4x + 12=(x³ - 3x²) - (4x - 12)=x²(x-3)-4(x-3)= (x-3)(x²-4)=(x-3)(x-2)(x+2)
 equation cross x-axis in point x=-2, x=2, x=3
so we can choise from  1 and 3 answers:
 <span>It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3.
It starts up on the left and goes down on the right and intersects the axis at x = -2, 2, and 3.</span>

coefficient before x³>0 so it go up
 so it ís answer 1
Answer:
1.  <span>It starts down on the left and goes up on the right and intersects the x-axis at x = -2, 2, and 3</span>

kiruha [24]3 years ago
6 0
The answer is A.

The 0's of the function are -2, 2, and 3.

The graph starts from the bottom left and it keeps going to the top right.

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7 0
4 years ago
The triangles in the figure are similar: ΔABC ∼ ΔDEF. Which of the following statements must be true? options: A) AB/DE=BC/EF=CA
VikaD [51]

Answer:

Answer A

Step-by-step explanation:

We see that ABC is similar to DEF. Pay attention to the order of these letters. The order that they read (left-to-right) is the order that they are similar. For example, AB is similar to DE. Despite being different triangles, they are both the <em>first two </em>letters in the triangle. So, knowing this, we can conclude that answer choice A is correct.

7 0
3 years ago
Read 2 more answers
Solve the given equation.<br><br><br><br> 8x = 168<br><br> what is x
V125BC [204]

Answer:

The Answer is gonna be 21

EXPLANATION :

8x = 168

x=168/8

x=21

This is the right Answer :3

I hope you are having a great day ❤️

5 0
2 years ago
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Choose the equation that best represents the general form of the following expression. x^2/2=7x user: what is the value of "c" i
AlexFokin [52]
X^2/2 = 7x
x^2 = 14x
x^2 - 14x = 0


A quadratic equation is of the form ax^2 + bx + c
Therefore, in 3x^2 + 5x + 7, c = 7
4 0
3 years ago
Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
3 years ago
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