F(x)=3x²-6x+13
a=3, b=-6, c=13
the x coordinate of the vertex is x=-b/(2a), so x=-(-6)/(2*3)=1
when x=1, y=3(1)²-6(1)+13=10
the vertex is at (1,10)
answers are in bold.
V: volume of a cone = (πr²h)/3 = 104.67 in³
π: pi = 3.14
r: radius = 1/2 diameter = [unknown]
h: height = 4 in
V = (πr²h)/3
V = r²(πh)/3
r² = (3V)/(πh)
r² = (3 ×104.67)/(3.14 × 4)
r² = 25
r = √25
r = 5 (but remember the radius is only 1/2 the diameter)
thus . . .
<u><em>d = 10 in </em></u>
Answer:
$6.66 and $7.04
Please give me brainliest, I really need it.
(1, 3.5 ) and (3, 3.5 )
the endpoints of the midsegment are at the midpoints of DE and DF
using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)
midpoint of DE = [
(0 + 2),(7 + 0)] = (1, 3.5)
midpoint of DF = [(0 + 6),(7 + 0)] = (3, 3.5)
