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nlexa [21]
3 years ago
15

Standard Heat of Formation: The enthalpy change for the formation of 1 mol of a substance in its standard state from its constit

uent elements in their standard states. True/ false?
Chemistry
1 answer:
12345 [234]3 years ago
6 0

The given statement about standard heat of formation is true.

Explanation:

Yes, it is true that standard heat of formation is same as standard enthalpy of formation. As enthalpy is termed for change in the heat energy occurred in the process of completion of any chemical reaction, the standard enthalpy or heat of formation is termed as the heat energy required to form 1 mole of any substance in its standard state from its original, parent or constituent elements in their standard state. Basically, it defines the amount of energy required by the system or compound for its formation from different elements under different synthesis conditions but the nature of the parent samples and temperature and pressure should be kept standard.

So the given statement is true.

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Manganese(IV) oxide is reduced to manganese(II) oxide by hydrogen gas. Include all phases in answer
liq [111]
<span><span>Mn<span>O<span>2<span>(s)</span></span></span>+<span>H<span>2<span>(g)</span></span></span>→Mn<span>O<span>(s)</span></span>+<span>H2</span><span>O<span>(g)</span></span></span></span>
4 0
3 years ago
Classify the following aqueous solutions as: strong acid, weak acid, neutral, weak base, or strong base.
kirill [66]

Vinegar pH 3.2: Weak acid

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4 0
2 years ago
A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?
Yanka [14]
Answer:
                =   374.90 kPa 

Calculation:
                  As we know atm and kiloPascal are related to each other as,

                                         1 atm  =  101.325 kPa
So,
                                    3.70 atm  =   X
Solving for X,
                                     X  = (3.70 atm × 101.325 kPa) ÷ 1 atm

                                     X  =  374.90 kPa 
7 0
4 years ago
Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?
Kipish [7]
pV = nRT

p = nRT/V 

p= 1 x 0.08205 x 1000/ 2

p = 41.025 Pa  

Edit: The unit should be atm instead of Pa, as pointed out by a nice human being.
4 0
4 years ago
Read 2 more answers
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konstantin123 [22]
Equation: MgOH2 (s) --> MgO (s) + H2O (g)

And it's already balanced.

I had chemistry this semester too.
3 0
3 years ago
Read 2 more answers
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