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nlexa [21]
3 years ago
15

Standard Heat of Formation: The enthalpy change for the formation of 1 mol of a substance in its standard state from its constit

uent elements in their standard states. True/ false?
Chemistry
1 answer:
12345 [234]3 years ago
6 0

The given statement about standard heat of formation is true.

Explanation:

Yes, it is true that standard heat of formation is same as standard enthalpy of formation. As enthalpy is termed for change in the heat energy occurred in the process of completion of any chemical reaction, the standard enthalpy or heat of formation is termed as the heat energy required to form 1 mole of any substance in its standard state from its original, parent or constituent elements in their standard state. Basically, it defines the amount of energy required by the system or compound for its formation from different elements under different synthesis conditions but the nature of the parent samples and temperature and pressure should be kept standard.

So the given statement is true.

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What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0
3 years ago
What is pH a measure of?
s344n2d4d5 [400]
It measures the acidity/basic level, that rules A out
hope this helped a little
4 0
3 years ago
Read 2 more answers
The balanced chemical equation for the combustion of butane is: 2C2H2 + 5O2 CO2 + 2H2O 2CH4 + 5O2 2CO2 + 4H2O 2C4H10 + 13O2 8CO2
SCORPION-xisa [38]
Butane is C₄H₁₀.

C_4H_{10} + O_2 \to CO_2 + H_2O \\ \\
\hbox{balance carbon and hydrogen on the right-hand side:} \\
C_4 H_{10} + O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\
\hbox{balance oxygen on the left-hand side:} \\
C_4 H_{10} + \frac{13}{2} \ O_2 \to 4 \ CO_2 + 5 \ H_2O \\ \\
\hbox{multiply by 2 to get rid of the fraction:} \\
2 \ C_4H_{10} + 13 \ O_2 \to 8 \ CO_2 + 10 \ H_2O

The balanced equation is 2 C₄H₁₀ + 13 O₂ <span>→</span> 8 CO₂ + 10 H₂O.
3 0
3 years ago
If 20.0 grams of Al is placed into a solution containg
meriva

Answer:

m H2(g) = 2.241 g H2(g)

Explanation:

  • 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)

limit reagent:

∴ Mw Al = 26.982 g/mol

∴ Mw H2SO4 = 98.0785 g/mol

⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al

⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4

⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2

∴ Mw H2 = 2.016 g/mol

⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2

5 0
3 years ago
Which product forms from the synthesis reaction between lithium (Li) and oxygen (O)?
Advocard [28]

Answer:

A Li2O

Explanation:

Li has a 1+ charge and O has a 2- charge so to balance the charges there needs to be 2 Li for every 1 O

5 0
3 years ago
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