A solar eclipse occurs when the A solar eclipse occurs when the the moon's shadow touches Earth. moon passes into the Earth's sh
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1) In a perfectly inelastic collision, the two balls stick together after the collision. In this type of collision, the total kinetic energy of the system is not conserved, while the total momentum is conserved.
If we call
the final velocity of the two balls that stick together, the conservation of the total momentum before and after the collision can be written as
(1)
where
is the mass of ball A
is the mass of ball B
is the initial velocity of ball A
is the initial velocity of ball B (taken with a negative sign, since it goes in the opposite direction of ball A)
If we solve (1) to find, we find that the final velocity of the balls is
and the positive sign means the two balls are going to the right.
2) I assume here we are talking about an elastic collision. In this case, both total momentum and total kinetic energy are conserved:
where
is the final velocity of ball A
is the final velocity of ball B
If we solve simultaneously the two equations, we find:
So, after the collision, ball A moves to the left with velocity v=-2 m/s and ball B moves to the right with velocity v=16 m/s.
3) The total momentum before and after the collision is conserved.
In fact, the total momentum before the collision is:
and the total momentum after the collision is:
If we call
where
If we solve (1) to find
and the positive sign means the two balls are going to the right.
2) I assume here we are talking about an elastic collision. In this case, both total momentum and total kinetic energy are conserved:
where
If we solve simultaneously the two equations, we find:
So, after the collision, ball A moves to the left with velocity v=-2 m/s and ball B moves to the right with velocity v=16 m/s.
3) The total momentum before and after the collision is conserved.
In fact, the total momentum before the collision is:
and the total momentum after the collision is:
The options of the question are missing. I have attached it.
Answer:
Satellite in option B will have the greatest speed.
Explanation:
From kepplers third law, we know that
V² = GM/R
Thus, v = √(GM/R)
Where;
v is velocity
G is gravitational constant
M is mass
R is radius
Looking at the options, let's start from the first one;
Option A
Here, mass = (1/2)m and radius = R
So, v = √(GM/R) thus v = √(G(m/2)/R) = √(Gm/2R)
Option B
Here, mass = m and radius = (1/2)R
Thus v = √(Gm/(R/2)) = √(2Gm/R)
Option C
Here, mass = m and radius = R
Thus v = √(Gm/R)
Option D
Here, mass = m and radius = 2R
Thus v = √(Gm/(2R))
Now, inspecting all the options, it's clear that option B will have the greatest velocity because it's numerator is the biggest and will in turn lead to higher velocity.
