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klemol [59]
2 years ago
10

Thirty-five coulombs of charge flow through a wire in 2 minutes. determine the current in the wire.

Physics
1 answer:
worty [1.4K]2 years ago
5 0

Thirty-five coulombs of charge flow through a wire in 2 minutes accounts for around 0.29167 amperes in the current wire.

Given:

Electric charge= 30 coulomb

Time for which charge flows through a wire = 2 minutes = 120 seconds

To find:

Electric current flowing in a wire=?

To calculate electric current understand the concept:

An electric current is the flow of charged particles through the conducting material.

The Standard International unit of electric current is Ampere or amp or A.

One ampere is defined as the flow of one-coulomb electric charge in one second.

It can be calculated as follows:

Electric current (Ampere) = Electric charge(Coulomb) ÷ time(seconds)

Electric current (A) = 35 C ÷ 120 s

Electric current = 0.29167 amperes

Hence, the electric current is flowing at the rate of 0.29167C/s or 0.29167 Ampere through a wire.

Learn more about electric current here,

brainly.com/question/2264542

# SPJ4

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3 years ago
HELP
Free_Kalibri [48]

Answer:

Explanation:

Although there is absolutely NO regard for significant digits, I can help you with this, nonetheless.

The equation for Potential Energy is PE = mgh. We have everything but the height of the ball. We have to solve for that using a one-dimensional motion equation:

v² = v₀² + 2aΔx, where Δx is our displacement (the height we need for PE). Filling in and keeping in mind that at the max height of parabolic travel, the final velocity of the object is 0:

0 = (21.5)² + 2(-9.8)Δx and

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8 0
3 years ago
It is known that birds can detect the earth's magnetic field, but the mechanism of how they do this is not known. It has been su
san4es73 [151]

Answer:

EMF = 5.01 \times 10^{-4} Volts

Explanation:

Here we know that the EMF induced in this Field is given as

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v = speed of the bird

L = length of the wings

now we have

B = 5\times 10^{-5} sin40

v = 13 m/s

L = 1.2 m

now we have

EMF = (13)(3.21 \times 10^{-5})(1.2)

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8 0
3 years ago
Two identical 0.400 kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the s
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Answer:

0.853 m/s

Explanation:

Total energy stored in the spring = Total kinetic energy of the masses.

1/2ke² = 1/2m'v².................... Equation 1

Where k = spring constant of the spring, e = extension, m' = total mass, v = speed of the masses.

make v the subject of the equation,

v = e[√(k/m')].................... Equation 2

Given: e = 39 cm = 0.39 m, m' = 0.4+0.4 = 0.8 kg, k = 1.75 N/cm = 175 N/m.

Substitute into equation 2

v = 0.39[√(1.75/0.8)

v = 0.39[2.1875]

v = 0.853 m/s

Hence the speed of each mass = 0.853 m/s

7 0
3 years ago
Newton s third law of motion states that every action has an __________ but __________ reaction.
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Newton´s thrid law of motion states that:
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c. equal, opposite.
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