The first half reaction is:
Sn+ -> Sn2+
You add 1 electron on the right side:
Sn+ -> Sn2+ + 1e-
The second half reacation is:
Ag+ -> Ag
You add 1 electron to the left side:
Ag+ + 1e- -> Ag
Then, you combine both reactions to get the balanced overall reaction since both half reactions have 1 electrons on the right and left side, respectively. You get:
Sn+ + Ag+ -> Sn2+ + Ag
Answer:
you could've googled it but here.
Explanation:
The former OSHA limit for sodium hydroxide (also known as caustic soda or Iye) was 2 mg/m3 as an 8-hour TWA. OSHA proposed a 2-mg/m3 ceiling limit for sodium hydroxide, based on the ACGIH- and NIOSH-recommended limits.
<u>Answer:</u> The density of substance is ![3.38g/cm^3](https://tex.z-dn.net/?f=3.38g%2Fcm%5E3)
<u>Explanation:</u>
To calculate density of a substance, we use the equation:
![\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%20of%20substance%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20substance%7D%7D%7B%5Ctext%7BVolume%20of%20substance%7D%7D)
We are given:
Mass of substance = 61.6 g
Volume of substance = ![18.2cm^3](https://tex.z-dn.net/?f=18.2cm%5E3)
Putting values in above equation, we get:
![\text{Density of substance}=\frac{61.6g}{18.2cm^3}\\\\\text{Density of substance}=3.38g/cm^3](https://tex.z-dn.net/?f=%5Ctext%7BDensity%20of%20substance%7D%3D%5Cfrac%7B61.6g%7D%7B18.2cm%5E3%7D%5C%5C%5C%5C%5Ctext%7BDensity%20of%20substance%7D%3D3.38g%2Fcm%5E3)
Hence, the density of substance is ![3.38g/cm^3](https://tex.z-dn.net/?f=3.38g%2Fcm%5E3)
Cesium is the biggest, atom wise.It has 55 protons.
Answer:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
Explanation:
The reaction is:
3AgNO₃ (aq) + Na₃PO₄(aq) → Ag₃PO₄(s) ↓ + 3NaNO₃(aq)
3 moles of silver nitrate and 1 mol of sodium phosphate, react in order to produce 1 mol of solid silver phosphate 3 moles of sodium nitrate
3Ag⁺(aq) + PO₄³⁻ (aq) → Ag₃PO₄(s) ↓