The atomic weight is numerically equivalent to the molar mass.
therefore molar mass of gold is - 197.2 g/mol
avagadros number states that 1 mol of any substance is made of 6.022 x 10²³ units. These units could be atoms making up elements or molecules making up compounds.
1 mol of gold is made of 6.022 x 10²³ atoms of gold
since 1 mol weighs 197.2 g
therefore if 197.2 g of gold contains - 6.022 x 10²³ atoms of gold
then 7.5 g contains - 6.022 x 10²³ x 7.5/ 197.2 = 2.29 x 10²² atoms of gold
answer is 2.29 x 10²² atoms of gold
Answer:
The ionic radii increase as the atomic numbers increase.
Explanation:
As we go down a Group, we are adding one more electron shell to the ion.
Each successive shell is bigger than the one before it, so the ionic radius should increase with increasing atomic number.
Here is a table of the ionic radii of the X⁻ ions.
<u>Element </u> <u> Z </u> <u> </u><u>r/pm
</u>
F 9 133
Cl 17 181
Br 35 196
I 53 220
At 85 227
However, the relation between r and Z is not linear (see graph).
All we can say is the ionic radius increases as the atomic number increases.
Al S
1) <u> 35.94 </u> =1.33111 <u> 64.06 </u> = 2.001875
27 32
2) = <u> 1.33111 </u> = <u> 2.001875 </u>
1.33111 1.33111
3) = ( 1 ) × 2 = ( 1.5 ) ×2
4) = 2 = 3
Empirical Formula = Al2S3
1) Divide the percentage given in question by the Relative Atomic Mass (RAM)
of the given elements.
2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.
3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)
Hope this helps you :)))
Please give this a brainliest
