P is True (x+x does indeed = 2x)
q is False ((3x)(-2y)=-6xy)
pVq is True (TvF is True)
p->q is False (p->q) equiv ~(p^~q) equiv ~(T^~F) equiv ~(T^T) = F
p^~q is True ((T^~F) = T^T = T)
p->~q is True (T->~F)
Answer:12
Step-by-step explanation:
Answer:
We have sufficient evidence to conclude at α = .05 that the husband’s perception would be higher than the wife’s.
Step-by-step explanation:
The hypotheses testing procedure in the given scenario is
H0: Husband’s perception would be similar to the wife’s i.e. μh=μw
Ha: Husband’s perception would be higher than the wife’s i.e. μh>μw
Level of significance: α=0.05
Test statistic: t=2.776
Critical region: t>t(0.05,9)=1.833
Conclusion: As the calculated value of t lies in critical region, so we reject our null hypothesis at 0.05 level of significance. Thus, we have sufficient evidence to conclude at α = .05 that the husband’s perception would be higher than the wife’s.
4-p=-4p+4
4-p+4p-4
3p
Step-by-step explanation:
that iw the answer
Answer:5 units!
Step-by-step explanation:
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