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3 years ago

What is the boiling point of methanol, if ∆H°for vaporization is 35.3 kJ/mol, and ∆S° for vaporization is 105 J/mol K?

Chemistry

1 answer:

QveST [7]3 years ago

6 0

Answer: 336.2K

Explanation:

The boiling point is obtained from the standard enthalpy and entropy of vaporization as shown in the image attached.

Standard enthalpy of vaporization=35.3KJmol-1=35.3×10^3 Jmol-1

Standard entropy of vaporization= 105 JMol-1K-1

The formula and details of the solution are shown in the image attached.

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Explanation

Given:

______HNO3 + Mg(OH)2 ------>

Solution:

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___HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + H₂O

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