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HACTEHA [7]
3 years ago
9

What is the boiling point of methanol, if ∆H°for vaporization is 35.3 kJ/mol, and ∆S° for vaporization is 105 J/mol K?

Chemistry
1 answer:
QveST [7]3 years ago
6 0

Answer: 336.2K

Explanation:

The boiling point is obtained from the standard enthalpy and entropy of vaporization as shown in the image attached.

Standard enthalpy of vaporization=35.3KJmol-1=35.3×10^3 Jmol-1

Standard entropy of vaporization= 105 JMol-1K-1

The formula and details of the solution are shown in the image attached.

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WORTH 20 POINTS Confirmation bias is where a scientist may change the data to support a certain bias.
Orlov [11]

Answer:

True

Explanation:

Confirmation Bias is the tendency to look for information that supports, rather than rejects, one’s preconceptions, typically by interpreting evidence to confirm existing beliefs while rejecting or ignoring any conflicting data

8 0
2 years ago
C4H10 is an example of a (n) a. Molecular formula b. Structural formula c. Atomic formula d. Geometric formula​
Oxana [17]

Answer:

molecular formula

Explanation:

hope it helps

8 0
3 years ago
A student compares the boiling point of substances having different intermolecular forces. which dependent variable did the stud
Gwar [14]

A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.

<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>

The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.

<h3>What properties are affected by intermolecular forces?</h3>

Intermolecular forces are measured by boiling points.

Intermolecular forces increase as bond polarization increases.

Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).

<h3>How can you determine strong and weak intermolecular forces?</h3>

Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.

Learn more about intermolecular forces:

<u><em>brainly.com/question/13479228</em></u>

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7 0
1 year ago
If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?
Nesterboy [21]

To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

PV = nRT

or T = PV / nR

 

So calculating:

T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]

<span>T = 375.35 K</span>

8 0
3 years ago
An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0025 M O2. At this temperature, Kc
pantera1 [17]

Answer:

5.35 *10^{-4}M

Explanation:

Equation for the reaction is as follows:

2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

By Applying the ICE Table; we have

                             2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

Initial                      x                  0.0025 M              0.0010 M

Change                  0                       0                            0

Equilibrium             x                  0.0025 M              0.0010 M

K_c =\frac{[CO_2]^2}{[CO]^2[O_2]}

Given that K_c = 1.4*10^2 ; Then:

1.4 *10^2 = \frac{(0.001)^2}{(x)^2(0.025)}

1.4 *10^2*0.025 = \frac{(0.001)^2}{(x)^2}

3.5 =( \frac{(0.001)}{(x)})^2

\sqrt {3.5} = \sqrt {( \frac{(0.001)}{(x)} )^2}

1.87=\frac{(0.001)}{(x)}

(x)= \frac{(0.001)}{1.87 }

x = 5.35 *10^{-4}M

∴ The equilibrium concentration of CO = x = 5.35 *10^{-4}M

7 0
3 years ago
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