It is +5. There -8 charge due to four oxygen atoms and +3 due to one sodium atom and 2 hydrogen atom which makes it necessary for phosphorus to have +5 charge on it to make the compound electrically neutral. The charge on phosphorus corresponds to its oxidation number.
Answer:
The concentration of chloride ion is 2.887 M.
Explanation:
Here we have a combination BaCl₂ and AlCl₃
1 mole BaCl₂ can produce 2 moles chloride ions as follows;
BaCl₂ → Ba²⁺ + 2Cl⁻
Therefore;
0.554 mole BaCl₂ can produce 2×0.554 moles chloride ions;
1 mole AlCl₃ can produce 3 moles chloride ions as follows;
AlCl₃ → Al³⁺ + 3Cl⁻
Therefore;
0.593 mole AlCl₃ can produce 3×0.593 moles chloride ions
Total concentration of chloride ions = 2×0.554 + 3×0.593 = 2.887 moles of Cl⁻ in 2×16.8 ml solution
The concentration of Cl⁻ is 2.887 M
Answer:
A
Explanation:
The formula used is
PV = P1 * V1
P = x
P1 = 4x
V1 = 1
V2 = ?
x * 1 = 4x * V2 Divide both sides by x
x/x = 4x /x * V2
1 = 4*V2 Divide by 4
1/4 = 4*V2/4
1/4 = V2
The answer is A
Answer:
Molar mass = 12.51 g/mol
Explanation:
V = 3L
P = 1.25 atm
T = 20 C = 20 + 273 = 293 K (Upon conversion to kelvin temperature)
n =?
m = 1.95g
Molar mass = ?
The variables are related by the follwing equation;
pV = nRT
where r = gas constant = 0.0821 L atm K−1
Solving for n, we have;
n = pV / RT
n = (1.25 * 3 ) / (0.0821 * 293)
n = 3.75 / 24.0553 = 0.1559 mol
The relationship between number of moles, n and molar mass is given as;
n = mass / molar mass
Molar mass = Mass / n = 1.95 / 0.1559
Molar mass = 12.51 g/mol
