If you know that the universe is estimated to be 14 billion years old . what is the age of the universe in seconds ???? (knowing
2 answers:
Answer:
<em>The estimated age of the universe is</em>
Explanation:
<u>Time Units Conversion</u>
Sometimes we need to express magnitudes in different units, depending on the specific situation handled in the question or problem at hand. Magnitudes like length, time, mass, temperature, pressure, etc., can be expressed in several different units.
The most common units for time are years, months, days, hours, minutes, and seconds. There are 3,600 seconds in one hour and 24 hours in one day.
We are given the estimated age of the universe as 14 billion solar years. If one solar year is 365.25 days long, then the age, expressed in days is
14,000,000,000 * 365.25 days
Some quantities need to be expressed in scientific notation. This is the case since the numbers are too high
There are 24*3600=86400 seconds in one day, so
The estimated age of the universe is
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The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m
Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:
Substitute numerical values:
The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
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