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3 years ago

FORMULA PLEASE AND explINATION

Physics

1 answer:

Alex_Xolod [135]3 years ago

7 0

2 Newtons to the right.

3 newtons are needed to over come the friction. There are 2 left over.

So the answer is 2 newtons to the right.

5 - 3 = 2

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Sitting = no movement
KE=0

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3 years ago

Someone help please by providing work and answers please :)

Nastasia [14]

First we gotta use an equation of motion:

$d = ut + \frac{1}{2} a {t}^{2}$

Our vertical distance d= 100 m, initial vertical speed u = 0 m/s (because velocity is fully horizontal), and vertical acceleration a = 9.8 m/s2 because of gravity. Let's plug it all in!

$100 = 0 + \frac{1}{2} (9.8) {t}^{2}$

Now we just need to solve for t:

${t}^{2} = \frac{2(100)}{9.8} \\ \\ t = \sqrt{\frac{2(100)}{9.8}}$

Hit the calculators, and you'll get 4.5 seconds!

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3 years ago

Which ONE of the following pairs of physical quantities consists of one scalar and one vector quantity?

lyudmila [28]

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

7 0

2 years ago

She sights two sailboats going due east from the tower. The angles of depression to the two boats are 42o and 29o. If the observ

Reika [66]

Answer:

The boats are 934.65 feet apart

Explanation:

Given:

The angles of depression to the two boats are 42 degrees and 29 degrees

Height of the observation deck i = 1,353 feet

To Find:

How far apart are the boats (y )= ?

Solution:

Step 1 : Finding the value of x(Refer the figure attached)

We can use the tangent ratio to find the x value

$tan(42^{\circ}) = \frac{1353}{x}$

$x = \frac{1353}{tan(42^{\circ}) }$

x = 590.47 feet

Step 2 : Finding the value of z (Refer the figure attached)

$tan(29^{\circ}) = \frac{1353}{z }$

$z = \frac{1353}{tan(29^{\circ})}$

z = 1525.12 feet

Step 3 : Finding the value of y (Refer the figure attached)

y = z -x

y = 1525.12 - 590.47

y = 934.65 feet

Thus the two boats are 934.65 feet apart

3 0

3 years ago

You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th

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To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

$T= 2\pi \sqrt{\frac{L}{g}}$