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2 years ago

Kon'nichiwa~please help me with this question!!

Physics

1 answer:

andrezito [222]2 years ago

4 0

Let's check the relationship

$\\ \rm\hookrightarrow g=\dfrac{GM}{r^2}$

$\\ \rm\hookrightarrow g\propto G$

Raindrops will fall faster . .
Also walking on ground would become more difficult as g increases.

Option C is wrong by now .Let's check D once

$\\ \rm\hookrightarrow T\propto \dfrac{1}{\sqrt{g}}$

So time period of simple pendulum would decrease.

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Americium-241 is a radioactive substance used in smoke detectors. The half life of americium is 432 years. If a smoke detector i

romanna [79]

Answer:

0.5 g

Explanation:

The half-life of a radioactive isotope is the time it takes for a certain amount of that isotope to halve.

In this case, we have an isotope of Americium-241, which has a half-life of

$\tau = 432 y$

This means that after 1 half-life (432 years), there will be an amount of americium equal to half its initial amount.

In this problem, the initial amount of americium is

$m_0 = 1 g$

Therefore, after 432 years (1 half-life), the amount of americium left will be half:

$m(432y) = \frac{m_0}{2}=0.5 g$

7 0

3 years ago

Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the

ivann1987 [24]

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

$x=vt$ (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s

You solve the equation (1) for t:

$t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s$

The time on which the bat hears the echo is twice the value of t, that is:

$t'=2(0.125s)=0.250s$

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

6 0

3 years ago

A 1500kg car double its speed from 50km/h to 100km/h. By how many times does the kinetic energy from the car's forward motion in

Rashid [163]

Answer:

Explanation:

Inital KE = (1/2) m v^2 = (1/2) * 1500 * 50^2 = 1,875,000 J

Final KE = (1/2) * 1500 * 100^2 = 7,500,000 J

But ,

4 * 1875000 = 7500000

so the KE has increased by 4 times.

8 0

3 years ago

Read 2 more answers

During which segments are two states of matter present?

dezoksy [38]

Answer:

the correct answer is D.) 2,4

3 0

4 years ago

If Rebecca is traveling at 7 m/s east for 1 hour how much is Rebecca displaced

Mekhanik [1.2K]

Answer:

25.2 km east

Explanation:

The relationship between velocity and displacement is given by:

$v=\frac{d}{t}$

where

v is the velocity

d is the displacement

t is the time

In this problem, we have:

$v=7 m/s$ east is Rebecca's velocity

$t=1 h=60 min=3600 s$ is the time taken

Re-arranging the equation, we can find Rebecca's displacement:

$d=vt=(7 m/s)(3600 s)=25,200 m=25.2 km$

and the direction is same as velocity (east)

3 0

3 years ago

Kon'nichiwa~please help me with this question!!​

Kon'nichiwa~please help me with this question!!