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Dmitry [639]
3 years ago
14

Spider-Man and Ned were testing the distance he could shoot his web depending on the angle at which he points his web shooter. H

e tested this 3 times at each angle.
0°: 18.2m, 16.7m, and 17.9m
45°: 79.6m, 74.3m, and 76.2m
75°: 62.4m, 61.5m, and 62.7m

What is the Independent variable?
Question 1 options:

The distance spider-man’s web shoots
The angle at which spider-man points his web shooter
Testing each angle 3 times
The location where they are testing

What is the dependent variable?

Question 2 options:

The distance spider-man’s web shoots
The angle at which spider-man points his web shooter
Testing each angle 3 times
The location where they are testing


Look at the 1st graph below, which location has the warmest temperatures in July?
Question 3 options: See Picture below

Barrow, Ak
Christchurch, NZ
Quito, Equador
Madison, WI

According to the 1st graph below, which location does not experience seasonal temperature fluctuations?

Question 4 options:

Barrow, AK
Quito, Equador
Christchurch, NZ
Madison, WI

Use the 2nd chart below to answer the following question. If cool stars are red and hot stars are blue, where would a bright (highly luminous) blue star be found on a Hertzsprung-Russell diagram?

Question 5 options:

Upper right
Lower right
Upper left
Lower left

A group of scientists has developed a computer program that will predict the phase that a star will be after a certain number of years. The scientists used data from real stars to teach the computer how the universe works. Now, it can be used to quickly run a simulation of what would likely happen over billions of years in the universe.

A group of students is wondering the rate at which a star progresses through life. They plan two experiments using computer simulations. They ran each simulation from the protostar phase 100 times and recorded the outcomes.

In Experiment 1 they used one size of star (1 solar mass) and compared seven different lengths of time. In Experiment 2 they used one length of time and 3 different sizes of stars (1, 15, and 30 solar masses). The results of both experiments are below in Figure 2

According to the 3rd data chart in which is the best conclusion of the changes occurring from 5-10 billion years?

Question 6 options:

Main sequence stars are becoming red giants.
Protostars are becoming red giants.
The stars are becoming black holes.
The stars are exploding.

Physics
2 answers:
lukranit [14]3 years ago
8 0

Answer:

1) The angle at which spider-man points his web shooter

2) The distance spider-man’s web shoots

3) Madison, WI

4) Quito, Equador

5) Upper left

6) Main sequence stars are becoming red giants.

Explanation:

1) The experimenters are choosing the angle at which to point the web shooter. This means the angle at which they shoot is independent of the other variables.

2) The distance the web shoots is not chosen by the experimenters and depends on the angle at which it is shot.

3) July is the 7th month and the graph for Madison, WI shows temperatures exceeding all other locations at this time.

4) Fluctuations refer to a changing of temperatures over seasons. Since Quito, Equador has a flat graph, this indicates no fluctuations.

5) This graph plots the hottest (blue) stars on the left and the highest luminosity (bright) stars at the top. Thus, bright blue stars are plotted in the top left.

6) At 5 billion years there are 0 giants and 100 main sequence stars. At 10 billions years there are 94 giants and 6 main sequence stars. This shows that the main sequence stars are becoming giants.

Serga [27]3 years ago
3 0

Answer:

3. Madison, WI

4. Quito, Equador

6. Main Sequence stars are becoming red giants

Explanation:

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rosijanka [135]

Answer:

+2m/s

Explanation:

average   velocity = displacement traveled / total time taken

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Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

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5 0
4 years ago
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Two masses of size m and 4m are connected by a massless thread and are strung over a frictionless pulley of radius R and moment-
tekilochka [14]

Answer:

Total kinetic energy of entire system is 3 mgl

Explanation:

Given two masses: m and 4m.

Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.

Total kinetic energy of entire system = decrease in gravitational potential energy of the system.

Therefore, we have :

ΔKE = Δp

ΔKE = 4mgl - mgl

= 3 mgl

Total kinetic energy of entire system is 3 mgl

6 0
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How far away is the moon?
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A box is sliding down an incline tilted at a 12° angle above horizontal. The box is initially sliding down the incline at a spee
OLga [1]

Answer:

The box will cover a distance of 0.9199m before coming to rest

Explanation:

We are given;

Angle of tilt; θ = 12°

Speed of sliding down; u = 1.5 m/s

Coefficient of kinetic friction; μ = 0.34

We are told that the box is sliding down an incline tilted at a 12° angle above horizontal.

Thus,

The components of the weight of the block would be;

Fx = mg sinθ = mg sin 12

Fy = mg cosθ = mg cos 12

For, the normal force on the block, it will be counter balanced by the Y component of weight of block and so we have;

Normal force; Fn = mg cos 12

Now formula for the frictional force would be given by;

Ff = μmg cos 12

So, Ff = 0.34mg cos 12

So, the net force along the inclined plane is;

Fnet = Fx - Ff

Fnet = mg sin 12 - 0.34mg cos 12

Where Fnet = mass x acceleration.

Thus;

ma = mg sin 12 - 0.34mg cos 12

m will cancel out to give;

a = g sin 12 - 0.34g cos 12

a = 9.81(0.2079) - 0.34(9.81 × 0.9781)

a = -1.223 m/s²

According to Newton's equation of motion, we have;

(v² - u²) = 2as

s = (v² - u²)/2a

Final velocity is zero. Thus;

s = (0² - 1.5²)/(2 × -1.223)

s = -2.25/-2.446

s = 0.9199 m

Thus, the box will cover 0.9199m before coming to rest

4 0
4 years ago
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