Enzymes that eventually break down the surface of bacteria are found in saliva, mucus, and tears, which act as chemical barriers against infection.
Enzymes found in saliva, mucous, as well as tears that degrade bacterial surfaces serve as chemical barriers preventing infection. The stomach's acid as well as the acid in sweat both destroy cellular pathogens, and even the semen contains antibacterial proteins.
There is no chemical and physical barrier offered by macrophages. Instead of acting as a barrier, macrophages target pathogens once they have already entered the body. Physical barriers include mucus as well as stratified squamous epithelium, whereas chemical barriers include saliva and urine.
Therefore, Enzymes that eventually break down the surface of bacteria are found in saliva, mucus, and tears, which act as chemical barriers against infection.
To know more about chemical barriers
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Answer:
(not sure if this helps but)
The number of electrons in a neutral atom is equal to its proton.
Explanation:
The number of protons in a neutral atom are equal to its number of protons. It is also equal to its atomic number.
hope it helps :)
Answer:
PH = 4.0
Explanation:
We are given;
Ka1 = 8.9 × 10^(-8)
Ka2 = 1.0 × 10^(-19)
From the 2 values of K given above, we can see that Ka2 is far smaller than Ka1.
Thus, Positive hydrogen ion (H+) will be majorly formed from first dissociation which is Ka1.
Now, the breakdown of the H2S solution is;
H2S⇌[H+] + [HS−]
Thus;
Ka1 = [[H+] × [HS2^(-)]]/(H2S)
HS2^(-) also has a positive hydrogen ion.
Thus, we can rewrite as;
Ka1 = [[H+] × [H+]]/(H2S)
Ka1 = (H+)²/(H2S)
Concentration of H2S is given as 0.1M. Thus;
8.9 × 10^(-8) = (H+)²/0.1
(H+)² = 0.1 × 8.9 × 10^(-8)
(H+) = √(0.1 × 8.9 × 10^(-8))
(H+) = 0.00009433981
Now, PH is gotten from;
PH = -log (H+)
Thus;
PH = -log 0.00009433981
PH ≈ 4.0
Answer:
The final temperature of the water will be 328.81 K .
Explanation:
Using the equation, <em>q = mcΔT</em>
here, <em>q = energy</em>
<em>m= mass</em>
<em>c= specific heat capacity </em>
<em>ΔT= change in temperature</em>
<em>Mass of water = 1kg (1000 g ) per liter</em>
<em>∴ 6.2 Liter of water = 6200 g</em>
<em>c of water ≈ 4.18 J /g/K</em>
<em>Now, </em>
<em>980000 = 6200*4.18*ΔT</em>
<em>ΔT = 37.81 K</em>
<em>∴ final temperature of the water = 291 + 37.81 = 328.81 K</em>
