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3 years ago

Which best describes the main difference between science and pseudoscience?

Physics

2 answers:

Kipish [7]3 years ago

6 0

C. Science is objective, and pseudoscience is subjective

Natali [406]3 years ago

5 0

It's the third option

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How lift force works in CER format

Step2247 [10]

The really good answer is 30cm CER format

3 0

3 years ago

A balanced 3-wire, 120/240V, single-phase circuit is connected so that the ungrounded conductors are from different transformer

sasho [114]

Answer:

$0\%$

Explanation:

A 3-wire, 120/ 240 V circuit from a three-phase delta transformer contains two ungrounded conductors and one grounded conductor. The grounded conductor carries the unbalanced current when the circuit is not balanced.

A neutral conductor has the same equal potential between it and all ungrounded conductors of a 3-wire system.

The current on the neutral conductor is $0\%$ percent of the ungrounded conductor current.

6 0

4 years ago

Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h

Dvinal [7]

Answer:

734.16 kg m/ $s^{2}$

Explanation:

The problem is asking for the Force of pushing off the ground.

The formula of Force is: F = mass x acceleration

Given = Mass: 600 newtons (N)

Acceleration: 12 m/ $s^{2}$

We have to convert the mass into kg first. Remember that 1 kg is equal to 9.80665 newtons.

Let x be the mass in newtons.

Let's convert: $\frac{1 kg}{9.80665 N}$ x $\frac{x}{600 N}$ = $\frac{600}{9.80665}$ = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/ $s^{2}$

F = 734.16 kg m/ $s^{2}$

7 0

3 years ago

6) Repeat experiment 5) a) but now use the stored energy meter. Why do you think the change takes place. charge remains constant

PilotLPTM [1.2K]

Answer:

the energy comes from the increase in the electric field

Explanation:

The capacitance is

C = ε₀ A / d

The electric charge on the condenser plates

Q = C ΔV

The stored electrical energy is

U = ½ C ΔV²

ΔV = E d

U = ½ (ε₀ A / d) (E d)²

U = ½ ε₀ A d E²

We see that the stored energy is proportional to the square of the electric field, so the capacitor can increase its energy with increasing voltage

In short, the energy comes from the increase in the electric field

5 0

3 years ago

A spaceship maneuvering near planet zeta is located at r⃗ =(600i^−400j^+200k^)×103km, relative to the planet, and traveling at v

slava [35]

Answer:

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

Explanation:

Initial location of spaceship = (600 i - 400 j + 200 k)* $10^3km$ = (600 i - 400 j + 200 k)* $10^6m$

Initial velocity = 9500 i m/s

Acceleration = (40 i - 20 k) $10^3m/s^2$

Time = 35 minute = 35 * 60 = 2100 seconds

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Substituting

$s= (9500 i)*2100+\frac{1}{2}*(40 i - 20 k)*2100^2\\ \\ s=9500*2100 i+20*2100^2i-10*2100^2j\\ \\ s=19.95*10^6i+88.2*10^6i-44.1*10^6j\\ \\ \\s=(108.15i-44.1j)*10^6m$

So final position = $((600 i - 400 j + 200 k)+(108.15i-44.1j))*10^6=(708.15 i - 444.1 j + 200 k)*10^6m$

= $(708.15 i - 444.1 j + 200 k)*10^3km$

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

3 0

3 years ago

Read 2 more answers