Answer:(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²
Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m
(a) Angular frequency w= 2πf
w= 2π × 760 = 4775.2Hz
(b) Maximum speed v is given as the product of angular frequency and maximum displacement
V=wx
V= 4775.2 × 0.00085
V= 4.06m/s
(c) The maximum acceleration a
= w²x
= (4775.2)² × (0.00085)
a= 19382.15m/s².
I believe the answer is "When a neutral atom looses an electron to another neutral atom, two charged atoms are created."
To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.
In this way,
The total mass of the cars would be,


Therefore the friction force at 29Km / h would be,




In this way the tension exerts between first car and locomotive is,



Therefore the tension in the coupling between the car and the locomotive is 
Answer:
A-500 N
Explanation:
The computation of the tension in the chain is shown below
As we know that
F = ma
where
F denotes force
m denotes mass = 7
And, a denotes acceleration
Now for the acceleration we have to do the following calculations
The speed (v) of the hammer is
v = Angular speed × radius
where,
Angular seed = 2 × π ÷ Time Period
So, v = 2 × π × r ÷ P
v = 2 × 3.14 × 1.8 ÷ 1
= 11.304 m/s
Now
a = v^2 ÷ r
= 70.98912 m/s^2
Now the tension is
T = F = m × a
= 7 × 70.98912
= 496.92384 N
= 500 N