Answer:
15435 J
Explanation:
Latent heat of fusion, Lf = 334 J/g
Specific heat of ice, ci = 2.1 J / g C
Latent heat of vaporisation, Lv = 2230 J/g
Specific heat of water, cw = 4.18 J / g C
mass, m = 50 g, T = - 5 degree C
There are following steps
(i) - 5 degree C ice converts into 0 degree C ice
H1 = m x ci x ΔT = 50 x 2.1 x 5 = 525 J
(ii) 0 degree C ice converts into 0 degree C water
H2 = m x Lf = 5 x 334 = 1670 J
(iii) 0 degree C water converts into 100 degree C water
H3 = m x cw x ΔT = 5 x 4.18 x 100 = 2090 J
(iv) 100 degree C water converts into 100 degree C steam
H4 = m x Lv = 5 x 2230 = 11150 J
Total heat required
H = H1 + H2 + H3 + H4
H = 525 + 1670 + 2090 + 11150 = 15435 J
