The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.
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Answer:
435 m
Explanation:
The precision with which the distance to the source of the earthquake can be estimated is equal to the difference in distance covered by the S- and P-waves in the time of 0.125 s.
The distance covered by each type of wave is given by
where
v is the speed of the waves
t is the time
For S-waves,
v = 3.74 km/s
t = 0.125 s
So the distance covered is
For P-waves,
v = 7.22 km/s
t = 0.125 s
So the distance covered is
So, the precision with which the distance can be determined is:
<h2>Greetings!</h2>
To find this value, you need to remember the speed formula:
3 = 6 / 2
Speed = distance ÷ time
Rearrange to make distance the subject:
Distance = speed * time
Simply plug these values into this:
5.6 * 8.25 = 46.2
<h3>So the player will travel 46.2 metres!</h3>
<h2>Hope this helps!</h2>
Answer:
Centripetal Acceleration = 2.701 m/s²
Explanation:
Given:
Starting from rest so initial angular velocity ωi = 0 rad/s
Final angular velocity ωf= 78 rev/min =78 × 2π /60 rad/s = 8.168 rad/s
Radius of Rim =d/2 =12/6= 6 in = 6× 2.54 cm =15.24 cm = 0.1524 m
angular acceleration α = (ωf - ωi)/t = (8.168 rad/s - 0 rad/s)/2.91 s
α =2.807 rad/s²
now to find angular velocity at 1.5 s we have
ω = α × t = 2.807 rad/s² × 1.5 s = 4.210 rad/s
so centripetal acceleration ac = ω² r = (4.210 rad/s)² × 0.1524 m
ac= 2.701 m/s²