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Finger [1]
3 years ago
5

Quick question plz.........If force acting on a body of mass 40kg is doubled. By how much will be the acceleration change?

Physics
2 answers:
Effectus [21]3 years ago
4 0

Answer:

A

Explanation:

F=ma

2F=2ma

If m stays constant, then the acceleration must double, or increase by a factor of 2. Therefore, the correct answer is choice A. Hope this helps!

klasskru [66]3 years ago
3 0

Answer:

if i'm not mistaken the answer is A

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During take-off a 8kg model rocket is burning fuel causing its speed to increase
77julia77 [94]

The strength of the thrust is 122 newtons.

The motion of the rocket is described by the second Newton's law, whose model is shown below:

\Sigma F = F - D = m\cdot a (1)

Where:

  • F - Thrust, in newtons
  • D - Drag, in newtons
  • m - Mass of the rocket, in kilograms
  • a - Net acceleration of the rocket, in meters per square second

If we know that D = 90\,N, m = 8\,kg and a = 4\,\frac{m}{s^{2}}, then the strength of the thrust is:

F = D + m\cdot a

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F = 122\,N

The strength of the thrust is 122 newtons.

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4 0
3 years ago
A radio-controlled car increases its kinetic energy from 3 J to 10 J over a distance of 1 m. What was the average net force on t
goldfiish [28.3K]

Answer:

Net force, F = 7 N

Explanation:

It is given that,

Initial kinetic energy of the car, K_i=3\ J

Final kinetic energy of the car, K_f=10\ J

Distance, d = 1 m

We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :

W=\Delta K

W=K_f-K_i

Also, W = F.d    d = distance and F = net force

F.d=K_f-K_i

F=\dfrac{K_f-K_i}{d}

F=\dfrac{10\ J-3\ J}{1\ m}

F = 7 Newton

So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.

8 0
3 years ago
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