Question

Is this equation x^9-5x3+6= 0 in quadratic form

Answer 1

No, it's not. A quadratic form is something like

$ax^2+bx+c=0$

They won't necessarily come in this exact form, but the important part is that there must be a constant term, and the other two terms must be powers of the variable, and one must be the square of the other.

In this case, for example, $x^2$ is the square of $x$

So, for example, an equation like

$-7x^8-5x^4+18$ is in quadratic form, because there is a constant term (18), and $x^8$ is the square of $x^4$. You can tell this because the exponents are one the double of the other.

So, in this case, you have $x^9$ which is the cube of $x^3$, so this equation is not in quadratic form.

Answer 2

Answer:

The equation is not quadratic in form.

The variable part of the first term is not the square of the variable part of the

second term.

The result of squaring x cubed is x to the 6th power, not the 9th power.

Step-by-step explanation: