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musickatia [10]
3 years ago
13

What do (3.9 x 10^2)(4.1 x 10^4) equal

Physics
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

Explanation:(3.9x100)(4.1x10,000)                

390x41,000

15,990,000

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What is the resistance of the coil A at 600 kelvin if its resistance at 300 kelvin is 50 ohms? (Assume the temperature coefficie
leonid [27]

155Ω

Explanation:

R = R ref ( 1 + ∝ ( T - Tref)  

where R = conduction resistance at temperature T

R ref = conductor resistance at reference temperature

∝ = temperature coefficient of resistance for conductor

T = conduction temperature in degrees Celsius

T ref = reference temperature that ∝ is specified at for the conductor material

T = 600 k - 273 k = 327 °C

Tref = 300 - 273 K = 27 °C

R = 50 Ω ( 1 + 0.007 ( 327 - 27) )

R = 155Ω

8 0
3 years ago
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A car is initially travelling at 12.1m/s It accelerates at a rate of -3.9m/s^2 for 7 seconds. What is it’s final velocity?
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It will be traveling in the reverse direction it was originally going at 15.2 m/s
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3 years ago
What is the formula that represents the simplest ratio of the atoms in the components
Dafna1 [17]

Answer:

Empirical formula

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5 0
3 years ago
The speed of light inside a medium is (2.0 x 10^8m/s) What is the index of refraction (n) of the medium?
kondor19780726 [428]

Answer:

Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium

1.5 = 3 x 108 / Speed of light in medium

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Explanation:

3 0
2 years ago
A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho
saul85 [17]

The change in kinetic energy is \Delta K = 3Fd

Explanation:

According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

W=K_f -K_i= \Delta K

where :

W is the work done on the object

K_f is the final kinetic energy of the object

K_i is the initial kinetic energy

Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):

W=F\Delta x

where

F is the magnitude of the force

\Delta x is the displacement of the object

In this problem, the force acting on the object is

F

While the displacement is the horizontal distance travelled, so

\Delta x = 3d

Therefore, the work done is

W=(F)(3d)=3Fd

And so the change in kinetic energy is

\Delta K = 3Fd

Learn more about work and kinetic energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

#LearnwithBrainly

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3 years ago
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