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4 years ago

What should happen to the demand for speed (measured by the average speed on highways) once airbags are included on cars?

1 answer:

6 0

Airbags diminish the expenses related with driving quick by diminishing injuries caused by fast speed crashes, in this manner the demand for speed increases, raising the average speed. Subsequently, wellbeing gadgets, for example, airbags and required safety belts tend to expand the security of car drivers and travelers (in spite of the fact that not as much as though there were no increase in speed) yet diminish the security of pedestrians.

The deployment of airbag can reduce the range of injuries to a number of parts of the body.

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brilliants [131]

Answer:

ok ty

Explanation:

5 0

3 years ago

Read 2 more answers

An airplane has an effective wing surface area of 19.4 m2 that is generating the lift force. In level flight the air speed over

alexgriva [62]

Answer:

W =23807.68 N

Explanation:

given,

surface area of wing = 19.4 m²

speed over top wing = 67 m/s

speed under wing = 51 m/s

density of air = 1.3 kg/m³

weight of plane

From Bernoulli's principle

$P_1 + \dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho_2^2$

where 1 and 2 are two different locations at the same geo potential level

so if we call 1 the lower surface and 2 the upper surface,

we find the pressure differential, P₁ -P₂

$\Delta P =\dfrac{1}{2}\rho (v_2^2-v_1^2)$

$\Delta P =\dfrac{1}{2}\times 1.3 \times (67^2-51^2)$

$\Delta P =1227.2\ N/m^2$

then the force acting on the plane is

F=P A

F=1227.2 x 19.4

F =23807.68 N

weight of the plane

W =23807.68 N

7 0

3 years ago

Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.4×109 electrons from one disk to the

allsm [11]

Answer:

r = 6.5*10^-3 m

Explanation:

I'm assuming you meant to ask the diameters of the disk, if so, here's it

Given

Quantity of charge on electron, Q = 1.4*10^9

Electric field strength, e = 1.9*10^5

q = Q * 1.6*10^-19

q = 2.24*10^-10

E = q/ε(0)A, making A the subject of formula, we have

A = q / [E * ε(0)], where

ε(0) = 8.85*10^-12

A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)

A = 2.24*10^-10 / 1.6815*10^-6

A = 1.33*10^-4 m²

Remember A = πr²

1.33*10^-4 = 3.142 * r²

r² = 1.33*10^-4 / 3.142

r² = 4.23*10^-5

r = 6.5*10^-3 m

3 0

3 years ago

The chart shows the masses of selected particles.

Molodets [167]

Answer: 0.2 u

Explanation:

The atomic mass of nuclide is written as a superscript. On the left (reactants) aide of the nuclear equation shown, the total atomic mass is 235.0 + 1.0 u = 236 u. On the right (products) side reaction, the total atomic mass is 137.9u + 94.9u + 3 x 1.0u = 235.8 u. Therefore, 0.2 mass units must have been converted into energy.

6 0

3 years ago

A proton moving at 6.60 106 m/s through a magnetic field of magnitude 1.80 T experiences a magnetic force of magnitude 7.60 10-1

Hoochie [10]

Hi there!

We can use the following equation for a point charge in a magnetic field:

$\large\boxed{F_B = qv \times B}$