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Crazy boy [7]
3 years ago
13

A bag contains 7 green marbles and 4 white marbles. You select a marble at random. What are the odds in favor of picking a green

marble?
Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

7 : 4 is the answer.

Step-by-step explanation:

A bag contains 7 green marbles and 4 white marbles.

bag contains total marbles = 7 + 4 = 11 marbles

you select a marble at random.

The probability is 7/11 to select green marble, but the odds are 7:4.

odds are different than probability that is favorable : unfavorable

That is 7 chances for and 4 against.

so the answer would be 7 : 4.

mixas84 [53]3 years ago
6 0
Ok, there's 11 marbles total so 65%
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<u>Solution</u><u>:</u>

\sqrt{4x + 13}  = x + 2

  • First square both sides.

=  > ( \sqrt{4x + 13} ) ^{2}  = (x + 2) ^{2}

  • Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

=  > 4x + 13 =  {(x)}^{2}  + 2 \times x \times 2 + (2) ^{2} \\  =  > 4x + 13 =  {x}^{2}   + 4x + 4

  • Now, transpose 4x and 4 to LHS.

=  > 4x - 4x + 13 - 4 =  {x}^{2}  \\

  • Now, do the addition and subtraction.

=  >  {x}^{2}  = 9 \\  =  >  x =  \sqrt{9}  \\  =  > x = ±3

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

Hope you could understand.

If you have any query, feel free to ask.

3 0
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