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3 years ago

11

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 m

ph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour?

1 answer:

jonny [76]3 years ago

6 0

Answer:

Speed of motorcycle is 40 mph and speed of car is 50 mph

Explanation:

Let the peed f the motorcycle is v m /sec

According to question speed of motorcycle = 2v-30 mph

Now it is given that in two hours car is 20 miles ahead from motorcycle

Distance traveled by motorcycle in 2 hour = 2v

And distance traveled by car in two hour = 2×(2v-30)

Now according to question

$2(2v-30)=2v+20$

4v-60 = 2v+20

2v = 80

v = 40 mph

So speed of motorcycle is 40 mph

And speed of car = 2v-30 = 2×40-30 = 50 mph

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Answer:

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F = 9×10^9 x 8×10^-6×10×10^-6/16

+

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A ball with an initial velocity of 8.00 m/s rolls up a hill without slipping. (a) Treating the ball as a spherical shell, calcul

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Answer:

Part i)

h = 5.44 m

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Explanation:

Part i)

Since the ball is rolling so its total kinetic energy in this case will convert into gravitational potential energy

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$\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = mgh$

here we know that for spherical shell and pure rolling conditions

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Part b)

If ball is not rolling and just sliding over the hill then in that case

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2 years ago

Read 2 more answers

Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$

Where,

$T$ - period

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Put the values,

$T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191$

Now, the angular displacement of the pendulum can be calculated by,

$\theta = A\times\rm \ cos(\omega T)$

Where,

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Put the values and calculate for $\omega$ ,

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Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

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