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Aleks [24]
3 years ago
5

A + 8 μC charge lies 4 m to the left of a - 10 μC charge. A - 12 μC charge lies 8 m to its right. What is the resultant force on

the center charge?
Physics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

both side charges will exert force on central charge towards left so the two forces add up. Thus resultant force on centre charge is

F = 9×10^9 x 8×10^-6×10×10^-6/16

+

9× 10^9 × 10×10^-6×12×10^-6/64

= 9× 10^9 × 10^ -12/16 (80+30)

=6.18 × 10^-2 N

or

= 0.06 N

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a group of scientists claim that a new type of fuel will help reduce greenhouse gas emissions. to evaluate this claim you can. A
Mariana [72]
A group of scientists claim that a new type of fuel will help reduce greenhouse gas emissions. to evaluate this claim you can a. calculate the price of producing the fuel. b. study the effect of a fuel spill on wetland ecosystems. c. determine the efficiency of the fuel in different types of engines. d. test the amount
5 0
3 years ago
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A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed
stich3 [128]

Answer:

Distance of closest approach, r=1.91\times 10^{-14}\ m

Explanation:

It is given that,

Charge on proton, q_p=e

Charge on alpha particle, q_a=2e

Mass of proton, m_p=1.67\times 10^{-27}\ kg

Mass of alpha particle, m_a=4m_p=6.68\times 10^{-27}\ kg

The distance of closest approach for two charged particle is given by :

r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}

r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}

r=1.91\times 10^{-14}\ m

So, their distance of closest approach, as measured between their centers 1.91\times 10^{-14}\ m. Hence, this is the required solution.

4 0
3 years ago
A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0
FromTheMoon [43]

Answer:

v_0 =1.71

Explanation:

the parabolic movment is described by the following equation:

y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2

where y is the height of the ball, a is the angle of launch, v_0 the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2

Finally, solving for v_0, we get:

v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}

v_0 =1.71

4 0
4 years ago
The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. In this problem you can appro
Pavel [41]

Answer:

A)A=12.2480\ m^2

B)12.2480\pm 0.1029\ m^2

Explanation:

<u>Given:</u>

Length of the room l= 3.92 ± 0.0035

Width of the room w= 3.15 ± 0.0055

A) Let A be the area of the room

A=l\times w\\A=3.92\times3.15\\A=12.2480\ \rm m^2

B)We will calculate uncertainty in each dimension

%uncertainty in length=\dfrac{0.0035}{3.92}\times 100=0.0892\ %

%uncertainty in width =\dfrac{0.0055}{3.15}\times 100=0.0174%

The uncertainty in area will be sum of uncertainty in length and width

%uncertainty in Area=  %uncertainty in length + %uncertainty in width

%uncertainty in Area=0.0892\ % + 0.0174\ %

%uncertainty in Area=0.0106

Uncertainty in Area=0.0106\times 12.2480=0.1029\ \rm m^2

There Area is12.2480 ± 0.1029\ \rm m^2

7 0
3 years ago
Which best explains how Selena can correct her error? She can change the magnets so like poles are facing each other. She can ch
alexandr402 [8]

Complete question is;

Selena drew a diagram to show how current moves in a loop of wire that is placed between two magnets. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire with green arrows at its ends away from the magnets pointing away from the magnets. Red arrows point from N to S. Which best explains how Selena can correct her error?

A) She can change the magnets so like poles are facing each other.

B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.

C) She can change the arrows so they show the magnetic field reversing direction between the magnets.

D) She can change the magnetic poles so they are both on one side of the loop.

Answer:

B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.

Explanation:

Since the direction of the arrows point north and south whereas the magnets are east and west, it means the arrows are not pointing in the correct direction. To correct it she will have to make sure the arrows are pointing in opposite directions of the magnet via the sides of the loop.

7 0
3 years ago
Read 2 more answers
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