Question

A + 8 μC charge lies 4 m to the left of a - 10 μC charge. A - 12 μC charge lies 8 m to its right. What is the resultant force on the center charge?

Answer 1

Answer:

both side charges will exert force on central charge towards left so the two forces add up. Thus resultant force on centre charge is

F = 9×10^9 x 8×10^-6×10×10^-6/16

+

9× 10^9 × 10×10^-6×12×10^-6/64

= 9× 10^9 × 10^ -12/16 (80+30)

=6.18 × 10^-2 N

or

= 0.06 N