In the y component, as at the beginning, the total momentum was 0 in this axis, the sum of both the first and struck ball has to be the same in opposite directions. In other words, both have the same magnitude but in opposite directions

$\begin{gathered} Py=0.71kg\cdot2.17\cdot sin(30) \\ Py=0.77kg\cdot m/s \end{gathered}$

This is for both balls after the collision, but one goes in a positive and the other in a negative direction.

7 0

1 year ago

Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.

igomit [66]

Answer:

$7.73544\times 10^{-21}kgm/sec$

Explanation:

We have given mass of helium nucleus $m=6.68\times 10^{-27}kg$

Velocity of helium nucleus $v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec$

Momentum of the helium nucleus is given by $P=mv$ where m is mass and v is velocity

So $P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec$

6 0

3 years ago

: Write your reflection after reading the statement below.

max2010maxim [7]

It was not the first time that a person who was in a few weeks ago, I

7 0

3 years ago

In the symbol 42He, the subscript 2 is the _____ for helium and the superscript 4 is the _____ for helium. atomic mass; atomic n

aleksklad [387]

Mass number ; atomic number

6 0

3 years ago

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