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Nataly_w [17]
4 years ago
13

What is the coefficient for H2O when the equation ? Ca(OH)2(aq) + ? H3PO4(aq) → ? Ca3(PO4)2(s) + ? H2O(ℓ) is balanced using the

smallest possible integers?
Chemistry
1 answer:
kari74 [83]4 years ago
7 0

Answer:

Coefficient of H_{2}O in the balanced equation with smallest possible integer is 6.

Explanation:

Unbalanced equation: Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance Ca: 3Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance PO_{4}  : 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance H and O: 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)

Balanced equation: 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)

So coefficient of H_{2}O in the balanced equation with smallest possible integer is 6.

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Answer:

d = 1.8 × 10⁻⁴ kg/L

Explanation:

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Moles of helium = 2 mol

Temperature and pressure = standard

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PV = nRT

V = nRT/ P

V = 2 mol × 0.0821 atm. L/ mol. K × 273 K / 1 atm

V = 44.8 L

Mass of helium:

Mass = number of moles  × molar mass

Mass = 2 mol × 4 g/mol

Mass = 8 g

Mass = 0.008 kg

Density;

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d = 0.008 kg/ 44.8 L

d = 1.8 × 10⁻⁴ kg/L

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4 years ago
Consider a solution that contains 0.274 M potassium chloride and 0.155 M magnesium chloride.
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Concentration of chloride ions = 0.584M

Explanation:

The step by step calculations is shown as attached below.

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Which phrase best describes the bond in H2
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4 years ago
How much heat is absorbed by a 112.5 g sample of water when it is heated from 12.5 °C to 92.1 °C? (Specific heat capacity of wat
Alborosie

Answer:

\boxed {\boxed {\sf37,467.72 \ Joules }}

Explanation:

We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

q=mc \Delta T

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.

  • ΔT= 92.1 °C - 12.5 °C= 79.6°C

Now we know three variables and can substitute them into the formula,

  • m= 112.5 g
  • c= 4.184 J/g °C
  • ΔT= 79.6 °C

q= (112.5 \ g )(4.184 \ J/g \textdegree C)(79.6 \textdegree C)

Multiply the first 2 numbers. Note the units of grams cancel.

q= (112.5 \ g *4.184 \ J/g \textdegree C)(79.6 \textdegree C)

q= (112.5  *4.184 \ J/ \textdegree C)(79.6 \textdegree C)

q= (470.7 \ J/ \textdegree C)(79.6 \textdegree C)

Multiply again. This time the units of degrees Celsius cancel.

q= (470.7 \ J/ \textdegree C *79.6 \textdegree C)

q= (470.7 \ J *79.6 )

q= 37467.72 \ J

37, 467.72 Joules of heat are absorbed by the sample fo water.

7 0
3 years ago
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