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Nataly_w [17]
3 years ago
13

What is the coefficient for H2O when the equation ? Ca(OH)2(aq) + ? H3PO4(aq) → ? Ca3(PO4)2(s) + ? H2O(ℓ) is balanced using the

smallest possible integers?
Chemistry
1 answer:
kari74 [83]3 years ago
7 0

Answer:

Coefficient of H_{2}O in the balanced equation with smallest possible integer is 6.

Explanation:

Unbalanced equation: Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance Ca: 3Ca(OH)_{2}(aq.)+H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance PO_{4}  : 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+H_{2}O(l)

Balance H and O: 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)

Balanced equation: 3Ca(OH)_{2}(aq.)+2H_{3}PO_{4}(aq.)\rightarrow Ca_{3}(PO_{4})_{2}(s)+6H_{2}O(l)

So coefficient of H_{2}O in the balanced equation with smallest possible integer is 6.

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2. What mass of water absorbs 6700 J of heat to raise the temperature from 283K to 318K?​
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In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3
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From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------>  Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3  = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

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1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles ×  2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced  is obtained from;

2 moles of HNO3  yields 1 mole of Ba(NO3)2

0.41 moles of HNO3  yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of  Ba(NO3)2  = 0.21 moles  × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

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