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2 years ago

A lithium atom contains 3 protons,4neutrons and 3 electrons.What would be formed if a proton was added to this atom.

Chemistry

1 answer:

slega [8]2 years ago

8 0

Answer:

Adding one proton to an atom of lithium with 3 protons, 4 neutrons and 3 electrons would form a _beryllium ion_. The new atom have 4 protons and 4 neutrons since Be has a mass number of 9 then it has to form an ion. Hope this helps! PLEASE GIVE ME BRAINLIEST!!!! =)

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Explain what Happens at the saturation point when adding salt to water at room temperature.

lorasvet [3.4K]

Answer:

See below

Step-by-step explanation:

You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.

However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.

The process is

NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)

The rates of the forward and reverse processes are equal, so you see no net change.

6 0

2 years ago

The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh

Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

$3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ$

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

$Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ$

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

$150.0 mL \times \frac{1.02g}{mL} = 153 g$

Given the specific heat capacity of the solution (c) is 4.184 J/g･°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

$Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J }{\frac{4.184J}{g.\° C } \times 153g} = 5.87 \° C$

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0

2 years ago

1. Energy changes occur as *

alexandr1967 [171]

Number 3 i think is <span>d.heat moves from an object of higher temperature to an object of lower temperature</span>

3 0

3 years ago

What is transitional elements

Gnesinka [82]

Answer:

any of the set of metallic elements occupying a central block (Groups IVB–VIII, IB, and IIB, or 4–12) in the periodic table, e.g., iron, manganese, chromium, and copper. Chemically they show variable valence and a strong tendency to form coordination compounds, and many of their compounds are colored.

Explanation:

5 0

2 years ago

Be sure to answer all parts. One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, whic

KIM [24]

Answer:

The answer is below

Explanation:

one gallon of gasoline produces 9.50 kg of carbon.

The total number of cars = 40 million

Distance covered by each car = 7930 miles

Consumption rate of the cars per miles traveled is 23.6 miles per gallon.

Hence the annual gasoline consumption by all the cars in the United States of America = (total number of cars × Distance covered by each car) ÷ Consumption rate of the cars per miles

annual gasoline consumption by all the cars = (40000000 × 7930 miles) ÷ 23.6 miles/gallon = `1.344067797 × 10¹⁰ gallons

1.344067797 × 10¹⁰ gallons = $1.344067797*10^{10}\ gallons *\frac{9.50\ kg}{1\ gallon} =1.276864407*10^{11}\ kg\ of \ carbon\ dioxide$

4 0

2 years ago