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harina [27]
3 years ago
15

How to balance that equation

Chemistry
1 answer:
zepelin [54]3 years ago
7 0

The balanced equation is

Cl₂ + SO₂ +2H₂O ⟶ 2Cl⁻ +SO₄²⁻ + 4H⁺

This is a <em>redox reaction</em>, so I will balance it using the <em>ion-electron method</em>.

<em>Step </em>1. Write the <em>skeleton equatio</em>n.

Strip the equation of H⁺ and H₂O (these come back in during the balancing procedure). We get

Cl₂ + SO₂ ⟶ Cl⁻ +SO₄²⁻

<em>Step 2</em>: Separate the skeleton equation into <em>two half-reactions</em>.

Cl₂ ⟶ Cl⁻

SO₂ ⟶ SO₄²⁻

<em>Step 3</em>: Balance all atoms <em>other than H and O</em>.

Cl₂ ⟶ 2Cl⁻

SO₂ ⟶ SO₄²⁻

<em>Step 4</em>: <em>Balance O</em>.

Add enough H₂O molecules to balance O,

Cl₂ ⟶ 2Cl⁻

SO₂ + 2H₂O ⟶ SO₄²⁻

<em>Step 5</em>: <em>Balance H</em>.

Add enough H⁺ ions to balance H.

Cl₂ ⟶ 2Cl⁻

SO₂ + 2H₂O ⟶ SO₄²⁻ + 4H⁺

<em>Step 6</em>:<em> Balance charge. </em>

<em>Add</em> <em>electrons</em> to the side that needs more negative charge.

Cl₂ + 2e⁻ ⟶ 2Cl⁻

SO₂ + 2H₂O ⟶ SO₄²⁻ + 4H⁺ + 2e⁻

<em>Step </em>7: <em>Add the two half-reactions</em>.

The balanced equation is

Cl₂ + SO₂ + 2H₂O ⟶ 2Cl⁻ + SO₄²⁻ + 4H⁺

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alculate the molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution.
valentina_108 [34]

The molarity of a solution that contains 20.0grams of sodium hydroxide in 200. ml of solution is 2.3 M.

<h3>What is Molarity? </h3>

Molarity is defined as the ratio of number of moles of solute to the volume of the solution.

Molarity = number of moles of solute/ Volume of solution

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given mass of sodium hydroxide= 20 g

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Firstly, we will calculate the moles of sodium hydroxide.

<h3>What is Mole? </h3>

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