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Answer:
C) SN2 and E2
Explanation:
For this question, we have analyzed the <u>substrate</u> and the <u>base/nucleophile</u>. The substrate, in this case, is 1-iodohexane and the base/nucleophile is potassium tert-butoxide.
<u>Substrate</u>
<u />
In the 1-iodohexane the iodide "I" is bonded to a primary carbon (carbon 1). Therefore we will have a <u>primary substrate</u>. If we have a primary substrate an Sn1 can not take place. We can not have a <u>primary carbocation</u> due to this instability. So, we can disccard options A) and B).
<u>Base/nucleophile</u>
<u />
In the potassium tert-butoxide we have an ionic compound. A positive charge is placed in the potassium atom a negative charge is placed in the oxygen of the ter-butoxide ion. So, we will have a <u>strong base</u> (a molecule with the ability to remove electrons) and a <u>strong nucleophile</u> (a molecule with ability to bond with an electrophile). With all this in mind, w<u>e can not have an E1 reaction</u>.
With both analyses, the answer is C).
See figure 1
I hope it helps!
Explanation:
Sol. 450 ml there is LiCl 200 g
Sol. 1000 ml there is LiCl 200/450×1000
= 444.44 g
Molar = g/molar mass = 444.44/42.394 = 10.48 M
<h3>Answer:</h3>
C6H12O6
Explanation:
To find empirical formular you write out the element
Carbon Hydrogen Oxygen
3.96 769 5.28
then u althrough divide by their atomic numbers
3.96÷ 12 769÷1 5.28÷16
=0.33 =769 =0.33
also divide althrough by the lowest number
the lowest number is 0.33 so we use it to divide
0.33÷0.33. 769÷0.33. 0.33÷0.33
= 1 = 2 = 1
empirical formular= CH2O
To find the Molecular formular
Molecular number = molar mass
(CH2O)n = 182
(12+1×2+16)n = 182
30n = 182
n = 6
therefore the Molecular formular is C6H12O6
Answer:
Noble gases already have a full outer shell, so they do no take part in chemical reactions.