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DaniilM [7]
4 years ago
7

True or false? A corollary statement that can be easily proved using a theorem.

Mathematics
1 answer:
Phantasy [73]4 years ago
8 0
True. <span>Corollaries are self-evident from theorems.</span>
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In scientific notation
Viefleur [7K]
The answer is 5 x 10*3
3 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Divide
IgorC [24]

Answer:

The answer is option 2.

Step-by-step explanation:

Firstly, you must factorize the possible expressions :

\frac{ {x}^{2} - 2x - 15 }{x - 3}  \div  \frac{x - 5}{ {x}^{2} - 9 }

=  \frac{(x - 5)(x + 3)}{x - 3}  \div  \frac{x - 5}{(x - 3)(x  + 3)}

Next you have to divide by converting to multiplication :

= \frac{(x - 5)(x + 3)}{x - 3}  \times  \frac{(x - 3)(x + 3)}{x - 5}

Lastly, you can cut out the similar expressions :

=  \frac{(x - 5)(x + 3)(x - 3)(x + 3)}{(x - 3)(x  -  5)}

=  {(x + 3)}^{2}

7 0
3 years ago
3. Two numbers are in the ratio 3:5. If their difference is 12, what are the numbers?​
vladimir2022 [97]
I got 18 and 30 for my answer
8 0
3 years ago
Using the slope​ formula, find the slope of the line through the given points.
UNO [17]

Answer:

0

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

  = (-5--5)/ (9--8)

 = (-5+5)/(9+8)

 = 0/17

=0

The slope it 0

This is a horizontal line because the y value doesn't change.  If the y value doesn't change, the slope it zero.

4 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
4 years ago
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