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nasty-shy [4]
4 years ago
7

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
garri49 [273]4 years ago
7 0

Answer:

m\angle R=69.4^o

Step-by-step explanation:

we know that

In the right triangle PQR

tan(R)=\frac{PQ}{QR} ----> by TOA (opposite side divided by adjacent side)

substitute the given values

tan(R)=\frac{8}{3}

using a calculator

m\angle R=tan^{-1}(\frac{8}{3})=69.4^o

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Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

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Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

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e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

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Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

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\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

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Step-by-step explanation:

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