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Svetlanka [38]
3 years ago
8

Convert -32 F into K

Chemistry
1 answer:
Afina-wow [57]3 years ago
4 0

Answer:

-32 Fahrenheit converts to 237.594 Kelvin

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(58 g)/ (4L) reduce units to one
katen-ka-za [31]

Answer is 14.5 g L⁻¹.

<em>Explanation;</em>

Here, the question says reduce the units as one.

The presented units are g/L. To reduce the units to one, what we can do is take L to the upper side.

This can be done according to the rules of indices;

1 / aˣ = a⁻ˣ

Like that, we can write 1 / L as L⁻¹.

Hence, the reduced unit is g L⁻¹.

But remember to keep a space between when writing two different units.

Actually, this is an unit for density.

3 0
3 years ago
How many elements are in Li2SO4?how many elements are in li2s 04 how many elements are in li2s 04 ​
Free_Kalibri [48]

Answer:

3

Explanation:

the three elements involved in this compound are Li, S, O.

lithium, sulfur, and oxygen. Which create the ionic compound, "Lithium Sulfate."

7 atoms total, since there are two lithium, four oxygen, and one sulfate atom. this is a white inorganic salt.

6 0
3 years ago
What are the 2 layers of continental crust called?​
noname [10]

Answer:

silica + aluminum or silica +magnetism

Explanation:

5 0
3 years ago
What is the value for ∆Soreaction for the following reaction, given the standard entropy values?
Soloha48 [4]
To get the ∆S of the reaction, we simply have to add the ∆S of the reactants and the ∆S of the products. Then, we get the difference between the ∆S of the products and the ∆S of the products. If the <span>∆S is negative, then the reaction spontaneous. If the otherwise, the reaction is not spontaneous.</span>
8 0
3 years ago
How many grams of aluminum chloride are produced when 6.73 g of aluminum react with an excess of chlorine gas?
sergejj [24]

Answer:

33.3 g AlCl3

Explanation:

First:

You need a balanced chem equation.

2Al + 3Cl2 --->2AlCl3

So now you use this to set up train track method which helps us cancel out the units. Also we dont care about chlorine because it is excess.

6.73g Al x 1mol Al/26.98g Al x 2mol AlCl3/2molAl x 133.34g AlCl3/1molAlCl3

= 33.3 g AlCl3

8 0
3 years ago
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