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laiz [17]
3 years ago
12

What is the percent composition by mass of sulfur in the compound MgSO4 (gram-formula mass =120. grams per mole)?(1) 20.% (2) 27

% (3) 46% (4) 53%
Chemistry
1 answer:
TEA [102]3 years ago
8 0
<span>Solving for the percent composition by mass of sulfur. The formula would be: %S = mass of sulfur / mass of compound x 100% Plugging in our data: %S = 32 amu / 120 amu x 100% %S = 0.266666 x 100% %S = 26.66% Rounded off to two significant numbers it will be 27%. Therefore the answer is number 2.</span>
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Plz help me solve this question is it A,B,C or D
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Answer:

c

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Stems are important plant structures because they _________.
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Fe2+(s) + Cr6+(aq) → Fe3+(aq) + Cr3+(aq)
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Read 2 more answers
Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units
KatRina [158]

Hello!

For this problem, we will be applying <em>Charles' Law</em>:

V1/T1 = V2/T2

Now that we have the formula, let's convert the temperature to Kelvin.

27 + 273 = 300K

Let's plug everything in now!

10/300 = 12.0/x

Simplified:

1/30 = 12.0/x

Cross-multiply:

1x = 30*12.0

<u>x = 360</u>

<em>Check!</em>

10/300 = 12/360

300*12 = 360*10

3600 = 3600

Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.

 

4 0
3 years ago
Two liters of oxygen (O2) is collected over water at 20oC. If the total pressure in the container is 95.00 kPa, what is the part
garri49 [273]

Answer:

THE PARTIAL PRESSURE OF OXYGEN GAS IN THE CONTAINER IS 92.67kPa WHICH IS OPTION B.

Explanation:

To calculate the partial pressure of oxygen gas collected over water, we use

Ptotal = Poxygen + P water

It is worthy to note that when oxygen is collected over water, it is mixed with water vapor and the total pressure in the container will be the sum of the pressure exerted by the oxygen gas and that of the water vapor at that given temperature.

At 20 C, the vapor pressure of water as given in the question is 2.33 kPa.

Using the above formula,

Ptotal = Poxygen + P water

Substituting for Poxygen, we have;

Poxygen = Ptotal - P water vapor

P oxygen = 95 .00 kPa - 2.33 kPa

P oxygen = 92.67 kPa.

The partial pressure of oxygen gas in the container is hence, 92.67kPa.

3 0
3 years ago
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