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Naya [18.7K]
3 years ago
14

What is the percent yield of water produced when 138 g ethyl alcohol, c2h5oh, is combusted in excess oxygen, if the actual exper

iment generated 150 g water?

Chemistry
1 answer:
kvasek [131]3 years ago
5 0
Hope this helps you.

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A major textile dye manufacturer developed new yellow dye. The dye has a percent composition of 75.9 5% C, 17.72% N
AnnZ [28]

Answer:

Such molecule must have molecular formula of C15N3H15

Explanation:

Mass of carbon in such molecule

0.7595*240_{g/mol} =182.28_{g C/mol}

The atomic mass of carbon is 12.01 g/mol, so in 182.28 g of carbon there is 15.18 mols of carbon.

Mass of Nitrogen in such molecule

0.1772*240_{g/mol} =37.73_{g C/mol}

The atomic mass of nitrogen is 14.01 g/mol, so in 42.53g of nitrogen there is 3.04 mols of nitrogen.

Mass of Hydrogen in such molecule

0.0633*240_{g/mol} =15.19 {g C/mol}

The atomic mass of Hydrogen is 1.00 g/mol, so in 15.19 g of Hydrogen there is 15.19 mols of Hydrogen.

Such molecule must have molecular formula of C15N3H15

5 0
3 years ago
Which of these formulas is NOT consistent with the guidelines for creating ionic compounds? Mark all that apply.
iVinArrow [24]

Answer:

d

Explanation:

because boron and fluorine are both nonmetals and don't fit the guidlelines for creating ionic compounds

8 0
3 years ago
Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the boiling of water, and exp
Sedbober [7]

Answer:

ΔH > 0; ΔS >0; ΔG = 0

Not spontaneous when T < 100 °C;

         Equilibrium when T = 100 °C

      Spontaneous when T > 100 °C

Step-by-step explanation:

The process is

H₂O(ℓ) ⇌ H₂O(g)

ΔH > 0 (positive), because we must <em>add heat</em> to boil water

ΔS > 0 (positive), because changing from a liquid to a gas i<em>ncreases the disorder </em>

ΔG = 0, because the liquid-vapour equilibrium process is at <em>equilibrium</em> at 100 °C

ΔG = ΔH – TΔS

Both ΔH and ΔS are positive.

If T = 100 °C, ΔG =0. ΔH = TΔS, and the system is at equilibrium.


If T < 100 °C, the ΔH term will predominate, because T has decreased below the equilibrium value.

ΔG > 0. The process is not spontaneous below 100 °C.


If T > 100 °C, the TΔS term will predominate, because T has increased above the equilibrium value.

ΔG < 0. The process is spontaneous above 100 °C.

4 0
3 years ago
To fine the number of neutrons in an atom, subtract its_____
storchak [24]

a is the answer hope this helps

3 0
3 years ago
Can someone help me, please?
DENIUS [597]
The answer to this question is: B) 3+
7 0
3 years ago
Read 2 more answers
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