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nadya68 [22]
3 years ago
14

Devon needs 90mL of a 10% acid solution for a science experiment. He has available a 5% solution and a 20% solution. How many mi

lliliters of the 5% solution and how many milliliters of the 20% solution should he mix to make the 10% solution?
Chemistry
1 answer:
Stels [109]3 years ago
6 0

Answer:

Devon needs add 60 mL of 5% acid solution and 30 mL of 20% acid solution

Explanation:

It know acid and water concentration for every solution. 2 equation are proposed because there are two unknowns. V1= volume 5%acid and V2 =volume 20% acid

<em>Acid   </em>V1(0.05)+V2(0.2)=90mL(0.1)

<em>Water   </em>V1(0.95)+V2(0.8)=90mL(0.9)

Clearing V1 from acid equation having to: V1=180-4V2

Replacing V1 in water equation having to: (180-4V2)(095)+V2(0.8)=81

Clearing V2 = 30mL

Replacing in water equation V1(0.05)+30(0.2)=9  So, V1=60mL

I hope it helps

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Given :

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Initial pressure of NOBr , 1 atm .

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The equilibrium constant for the reaction .

Solution :

             2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s           1 atm                 0             0

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At equilibrium :

K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm

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Answer:

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Explanation:

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When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40
slava [35]
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

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The volume of a given mass of an ideal gas at constant pressure is
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Answer:

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