mass spectrum of tertiary butyl chloride having overall mass as 92 m /Z for Cl35 and 94 m /Z for Cl37. The major peak at 57 m /Z for the removal of chlorine - 37 radical whereas other peak appear at 77 m /Z after removal of a methyl radical.
Ir of tertiary butyl chloride appear majorly at 3000 Cm^-1 whereas other small peaks appear between 1400- 1550 Cm-1
Answer:-
0.648 M
Explanation:-
Volume of Ba(OH)2= 34.63ml/1000=0.03463 litre
Number of moles of Ba(OH)2 = 0.3275 M x 0.03463 litre
= 0.01134 moles
Since Ba(OH)2 has 2 OH in its formula,
Number of moles of OH- = 2 x 0.01134=0.02268 moles.
Volume of HCl= 35ml/1000 = 0.035 litre
At the end point number of moles of H+ = number of moles of OH-.
Number of moles of HCL= Concentration of HCl x Volume of HCl
∴ Concentration of HCl = 0.02268 moles/ 0.035 litre
= 0.648 moles/ litre
= 0.648 M
Answer:
P₂ = 2 atm
Explanation:
Given data:
Initial volume = 10.0 L
Initial pressure = 4.0 atm
Final volume = 20.0 L
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
4.0 atm × 10.0 L = P₂ × 20.0 L
P₂ = 40.0 atm. L/ 20.0 L
P₂ = 2 atm
Answer:
190n
Explanation:
190 190 and because it is easy to understand if you didn't understand my answer ask any man
