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djyliett [7]
3 years ago
6

mage result for alz... Warm-Up Exercises for Chapter 2 - Acid-Base Reactions roblem 2.3 H2O is the acid and NH2 is the base. Exp

ress your answers as a chemical expression. = AXO O ? H2O + NH4= Submit Previous Answers Request Answer X Incorrect; Try Again; 19 attempts remaining
Chemistry
1 answer:
laila [671]3 years ago
5 0
Type this question into apex learning! Gives you answer and step by step explanation
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1. start line drawn in ink

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The units of density are kg/m2. If the density of a liquid is 760.0 kg/m' what is the specific volume? a) 1.316 x 10 m2/kg b) 1.
zlopas [31]

Answer:

The correct answer is: 1.316 . 10⁻³ m³/kg.

Explanation:

The density (ρ) of a substance is the ratio of its <em>mass (m)</em> to its <em>volume (V)</em>. At constant temperature and pressure, its value is constant and it is an intrinsic property of materials. The units of density are kg/m³.

\rho = \frac{m}{V}

The specific volume (ν) of a substance is the ratio of its <em>mass</em> to its <em>volume</em>. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

\nu = \frac{V}{m}=\frac{1}{\rho }

Given we know the density of the liquid, we can use this relationship to find out its specific volume:

\nu =\frac{1}{\rho }=\frac{1}{760.0kg/m^{3} } =1.316 .10^{-3} m^{3} /kg

6 0
3 years ago
The state of matter that has molecules with the least random molecular arrangement:
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