The compound formed is calcium nitrate
Kp/Kc = RT
<h3>Further explanation</h3>
Given
Reaction
A(g) ⇌ C(g)+B(g)
Required
Kp/Kc
Solution
For reaction :
pA + qB ⇒ mC + nD
![\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKc%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
While the equilibrium constant Kp is based on the partial pressure
![\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKp%20~%20%3D%20~%20%5Cfrac%20%7B%5BpC%5D%20%5E%20m%20%5BpD%5D%20%5E%20n%7D%20%7B%5BpA%5D%20%5E%20p%20%5BpB%5D%20%5E%20q%7D%7D%7D%7D)
The value of Kp and Kc can be linked to the formula '

R = gas constant = 0.0821 L.atm / mol.K
Δn=moles products - moles reactants or
number of product coefficients-number of reactant coefficients
For reaction :
A(g) ⇌ C(g)+B(g)
number of product coefficients = 1+1=2
number of reactant coefficients = 1
Δn= 2 - 1 =1
So Kp/Kc = RT
The molality of the solution is 1.4 moles per kilogram (molal).
The molality of the solution is equal to the number of moles of sugar (solute) divided by the number of kilograms of water (solvent). Hence, the molality is determined below:


The molality of the solution is 1.4 moles per kilogram (molal).
We kindly invite to check this question on molality: brainly.com/question/4580605
Representative elements are also known as Group A elements.