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Brut [27]
3 years ago
15

For A = {a, b, c, d} fin P(A), the power set of A. (Compare to example 0.3.3 0n p22) For A- (a, b, c, d) find P(A), the power se

t of A.
Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer: The required set is {∅, {a},{b},{c},{d},{a,b},{a,c},{b,c}{c,d},{b,d},{d,a},{a,b,c},{b,c,d},{a,c,d},{a,b,d},{a,b,c,d}}

Step-by-step explanation:

Since we have given that

A= { a,b,c,d}

So, n = 4

We need to find the power set of A.

Number of elements in power set of A is 2^n=2^4=16

So, the power set of A has 16 elements.

So, P(A) becomes {∅, {a},{b},{c},{d},{a,b},{a,c},{b,c}{c,d},{b,d},{d,a},{a,b,c},{b,c,d},{a,c,d},{a,b,d},{a,b,c,d}}

Hence, the required set is {∅, {a},{b},{c},{d},{a,b},{a,c},{b,c}{c,d},{b,d},{d,a},{a,b,c},{b,c,d},{a,c,d},{a,b,d},{a,b,c,d}}

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svetoff [14.1K]
<h2>Hello!</h2>

The answer is: g(x)=-\sqrt[3]{x-1}

<h2>Why?</h2>

Let's check the roots and the shown point in the graphic (2,-1)

First,

0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1

then,

g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1

So,  we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

(g(x)=-\sqrt[3]{x-1})

Second,

Evaluating the function at (2,-1)

y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1

-1=-1

It means that the function passes through the given point.

Hence,

The equation which represents g(x) is g(x)=-\sqrt[3]{x-1}

Have a nice day!

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3 years ago
Find the quotient: -10/19 divided by (-5/7) ?
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3 years ago
1/2(10p-7q) if p=9 and q=2
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Answer:

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Step-by-step explanation:

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I believe it is right by looking at this picture, but I am not certain

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In this question, you're solving for x.

Solve for x:

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Distribute the 2 to the variables inside the parenthesis.

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8 0
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