Answer: 5,000
Step-by-step explanation: 2,000 saved 250 per month so 250 times
In the number 14,423, the digit '4' comes up twice, in the thousand and hundred position.
The farther to the left a digit is, the higher that number is compared to another digit to the right of it.
This is why 1,000 is higher than 999.
In the number 14,423, there are two values for four: thousand (four thousand) and hundred (four hundred)
Answer:
is the value of x. Step-by-step explanation: We have been given the two terms which are equivalent means they have equal value: and . So, by the given information: we have to solve for x: Firstly, we will cross multiply so, we will get: After simplification we will get the final result is the value of x.
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Answer:
a) 0.5 = 50% of flanges exceed 1 millimeter.
b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
This means that 
(a) Determine the proportion of flanges that exceeds 1.00 millimeters.
0.5 = 50% of flanges exceed 1 millimeter.
(b) What thickness is exceeded by 90% of the flanges?
This is x for which:
So
A thickness of 0.96 millimeters is exceeded by 90% of the flanges
