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Brut [27]
3 years ago
15

Give an example of two elements that would form a covalent bond

Chemistry
1 answer:
Tamiku [17]3 years ago
4 0

<span>Hydrogen carbon and oxygen commonly form covalent bonds.
</span>
HOPE THIS HELPS!
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Como se representan los elementos en la tabla¿?
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Na sodiops los elementos químicos se representan como el átomo, el núcleo, donde se necuentran los protones y neutrones van dentro, los electrones afuera, girando de forma elíptica alrededor del núcleo. ... por ejemplo el oxígeno numero atómico 8, tiene 8 protones y 8 electrones. el número de neutrones es diferente.

Explanation:

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Please can someone explain the differences in variables (e.g. control variable, Independent variable and Dependent variable). I
7nadin3 [17]

Answer:

Independent Variable: The thing in an experiment which is changed.

Dependent Variable: The thing in an experiment which is affected by the change. (In other words, it's affected by the independent variable.)

Control Variable: The other factors of the experiment that remain unchanged.

For example, say you want to do an experiment about the effects of water on plant height. So, the independent variable, or the thing that is changed would be the amount of water, and the dependent variable would be the plant height, as the plant height is directly affected by the independent variable. Lastly, for this to be a fair experiment, there must be control variables. For example, all of the plants should be put in a room with equal temperature, they should get the same amount of sunlight, etc.

I hope this answers your question- feel free to ask me if you need any more help.

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Can you help me figure out how to determine the Conjugate Acid of Sodium Chloride - NACL ?
mars1129 [50]

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Explanations:

4 0
1 year ago
A home solar energy storage unit uses 4.75 ✕ 102 L of water for storing energy. On a sunny day, the water absorbed 2.75 ✕ 104 kJ
Sav [38]

Answer : The water's temperature change will be, 13.85^oC

Explanation : Given,

Density of water = 0.998 g/mL

Volume of water = 4.75\times 10^2L=4.75\times 10^5mL

(conversion used : 1 L = 1000 mL)

Specific heat of water = 4.184J/g^oC

Heat absorbed = 2.75\times 10^4kJ=2.75\times 10^7J

(conversion used : 1 kJ = 1000 J)

First we have to determine the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.998g/mL)\times (4.75\times 10^5mL)=474050g

Now we have to calculate the change in temperature of water.

Formula used :

Q=m\times C_w\times \Delta T

where,

Q = heat absorbed by water

m = mass of water

C_w = specific heat of water

\Delta T = change in temperature

Now put all the given value in the above formula, we get:

2.75\times 10^7J=474050g\times 4.184J/g^oC\times \Delta T

\Delta T=13.85^oC

Therefore, the water's temperature change will be, 13.85^oC

8 0
4 years ago
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