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Elena-2011 [213]
3 years ago
8

What is the distance of PQ with endpoints P (–3, 4) and Q (5, –8)

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:square root of 208

Step-by-step explanation: the difference of the X values is 8 and the diff of Y values is 12. 8 squared is 64 and 12 squared is 144. If both are added and square rooted, then it becomes sqrt 208

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Explanation:

f(x) = (x-4)(x+2)

1) For x-intercept, y will be 0

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<u />

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2) For vertex: x = -b/2a where ax² + bx + c

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ordered pair of vertex: (1, -9)

3) For y-intercept, x will be 0

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<u>y-intercept</u>: (0, -8)

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